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3 years ago

2. Write an expression to represent f (20)

Mathematics

1 answer:

Furkat [3]3 years ago

7 0

Answer:

I just learned this topic and have the same question, so I'm not sure if this right. However, I see a fellow student struggling and have to at least put in what I know. My equation was f(n) = 64(1/2)^n-1, then the question was write an expression to represent f(20).

Step-by-step explanation:

So, my answer was f(20) = 64(1/2)^19

f(20) is the number you plug into n. And because the exponent is n-1, I knew to subtract 1 from 20 to get 19.

Then I just wrote the equation out like the original expect with the numbers pluged in: f(20) = 64(1/2)^19

I hope this helps!

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What is the sum of (2x4 + 5x3 - 8x2 - x + 10) and (8x4 - 4x3 + x2 - x + 2)?

balu736 [363]

Option D: $10x^4+x^3-7x^2-2x+12$ is the right answer

Step-by-step explanation:

Given polynomials are:

$P_1 : 2x^4+5x^3-8x^2-x+10\\P_2: 8x^4-4x^3+x^2-x+2$

We have to find the sum of polynomials

So,

$S = P_1+P_2\\= (2x^4+5x^3-8x^2-x+10) + (8x^4-4x^3+x^2-x+2)\\=2x^4+5x^3-8x^2-x+10+8x^4-4x^3+x^2-x+2\\$

Combining like terms

$=2x^2+8x^4+5x^2-4x^3-8x^2+x^2-x-x+10+2\\= 10x^4+x^3-7x^2-2x+12$

Hence,

Option D: $10x^4+x^3-7x^2-2x+12$ is the right answer

Keywords: Polynomials, sum

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#LearnwithBrainly

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2 years ago

Read 2 more answers

Please solve the following sum or difference identity.

xxTIMURxx [149]

Answer:

$sin(A - B) = \frac{4}{5}$

Step-by-step explanation:

Given:

$sin(A) = \frac{24}{25}$

$sin(B) = -\frac{4}{5}$

Need:

$sin(A - B)$

First, let's look at the identities:

sum: $sin(A + B) = sinAcosB + cosAsinB$

difference: $sin(A - B) = sinAcosB - cosAsinB$

The question asks to find sin(A - B); therefore, we need to use the difference identity.

Based on the given information (value and quadrant), we can draw reference triangles to find the simplified values of A and B.

sin(A) = $\frac{24}{25}$

cos(A) = $\frac{7}{25}$

sin(B) = $-\frac{4}{5}$

cos(B) = $\frac{3}{5}$

Plug these values into the difference identity formula.

$sin(A - B) = sinAcosB - cosAsinB$

$sin(A - B) = (\frac{24}{25})(\frac{3}{5}) - (-\frac{4}{5})(\frac{7}{25})$

Multiply.

$sin(A - B) = (\frac{72}{125}) + (\frac{28}{125})$

Add.

$sin(A - B) = \frac{4}{5}$

This is your answer.

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Step-by-step explanation:

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