Carl's Television Assume that there are no cases that have interpreted the statute and no statutory definitions that apply.We know 18 televisions sets contains 3 defective.
sets => 15 TV sets are ok.So the total number of possible ways for the hotel to buy = C = 43758
At least one of the defective sets, SO we need to find the probability for 1 defective sets, 2 defective sets and 3 defective sets.1. The number of ways the hotel purchases 8 of these televisions sets but have 1 defective one:P() = C * C =6435*3 = 19305
2. The number of ways the hotel purchases 8
of these televisions sets but have 2 defective
one:P(2) = C C = 5005*3= 15015
3. The number of ways the hotel purchases 8
of these televisions sets but have 3 defective
one:P(3) = C5 *=3003*1 = 3003
So the probability that the hotel receives at least
one of the defective sets =(P() + P(2) + P(3) ) /P= (19305 +15015 +3003 ) /43785*100% = 85.29%.
The number of ways the hotel can receive at
least one defective set in a purchase of 8 sets is
calculated using the combination.
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