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3 years ago

32 is between which two perfect squares?

Mathematics

1 answer:

katovenus [111]3 years ago

3 0

Answer:

5 * 5 = 25 and 6 * 6 = 36 :)

Step-by-step explanation:

32 is between 5 * 5 = 25

and also between 6 * 6 = 36

those are both perfect squares

i hope this helps

You might be interested in

1 2/5m-3/5(2/3m+1) How do you solve this problem

igor_vitrenko [27]

Step-by-step explanation:

I am not sure what you mean by "solve".

I assume you mean simplify the expression.

and then it is very tricky to find the true original expression the way you typed it.

I think you meant

1 2/(5m) - 3/(5(2/(3m + 1)))

1 = 5m/5m

1 2/(5m) = (5m+2)/5m

3/(5(2/(3m + 1))) = 3/(10/(3m + 1)) = 3/1 / (10/(3m + 1))

when dividing by a fraction, it is the same as multiplying with the upside-down fraction

so, this is the same as

3/1 × (3m + 1)/10 = (3(3m + 1)) / (10×1) = (9m + 3)/10

this would give us in total

(5m + 2)/5m - (9m + 3)/10

to do the subtraction we need to bring both fractions to the save denominator (lower part).

it seems to me the easiest one would be 10m.

so,

2×(5m + 2)/10m - m×(9m + 3)/10m =

= (10m + 4)/10m - (9m² + 3m)/10m =

= (10m + 4 - 9m² - 3m)/10m = (-9m² + 7m + 4)/10m

if we want to transform this back to a sum of fractions :

4/10m - (9m² - 7m)/10m = 2/5m - (9m - 7)/10

5 0

2 years ago

Help please? even if someone gave me the steps to figure the answer myself, that'd be great

swat32

Answer:

The height is 28.57 cm.

The surface area is 9,628 cm^2.

Step-by-step explanation:

I assume the cooler is shaped like a rectangular prism with length and width of the base given, and with an unknown height.

volume = length * width * height

First, we convert the volume from liters to cubic centimeters.

60 liters * 1000 mL/L * 1 cm^3/mL = 60,000 cm^3

Now we substitute every dimension we have in the formula and solve for height, h.

60,000 cm^3 = 60 cm * 35 cm * h

60,000 cm^3 = 2,100 cm^2 * h

h = (60,000 cm^3)/(2,100 cm^2)

h = 28.57 cm

The height is 28.57 cm.

Now we calculate the internal surface area.

total surface area = area of the bases + area of the 4 sides

SA = 2 * 60 cm * 35 cm + (60 cm + 35 cm + 60 cm + 35 cm) * 28.57 cm

SA = 9,628 cm^2

The surface area is 9,628 cm^2.

8 0

3 years ago

I answered 2. Am I right?

GuDViN [60]

Answer:

Yes, I agree, the score of 2 was an outlier, outside of what is close to everyone else's score

Step-by-step explanation:

6 0

2 years ago

Hii does anyone know the answer to this? thank you! i’m a little confused since there’s no degrees

Leokris [45]

Answer:

1. AT = 9.43

2. TH = 9.43

3. MA = 7.81

4. MH = 7.81

Step-by-step explanation:

1. Determination of the length of AT.

Length of 1st leg = 8

Length of 2nd leg = 5

length of AT =.?

Using pythagoras theory, we can obtain the length of AT as illustrated below:

AT² = 8² + 5²

AT² = 64 + 25

AT² = 89

Take the square root of both side

AT = √89

AT = 9.43

2. Determination of the length of TH.

From the diagram given in the question above, we can see that length TH and length AT are the same i.e

TH = AT

AT = 9.43

Therefore,

TH = 9.43

3. Determination of the length of MA.

Length of 1st leg = 6

Length of 2nd leg = 5

Length of MA =?

Using pythagoras theory, we can obtain the length of MA as illustrated below:

MA² = 6² + 5²

MA² = 36 + 25

MA² = 61

Take the square root of both side

MA = √61

MA = 7.81

4. Determination of the length of MH.

From the diagram given in the question above, we can see that length MH and length MA are the same i.e

MH = MA

MA = 7.81

Therefore,

MH = 7.81

7 0

3 years ago

Can someone please help me on these two?

stellarik [79]

Answer:

Guided Practice 4: QR = 7.12

Guided Practice 5: x = 15

Step-by-step explanation:

Guided Practice 4:

Given that:

PR = $13 \frac{3}{4} ft = 13.75 ft$

PQ = $6\frac{5}{8} ft = 6.63ft$

QR = ?

PQ + QR = PR

6.63 + QR = 13.75

Subtract 6.63 from both sides of the equation to solve for QR:

6.63 - 6.63 + QR = 13.75 - 6.63

QR = 7.12

Check if QR is valid:

PQ + QR = PR

6.63 + 7.12 = 13.75

13.75 = 13.75 (true statement).

Guided Practice 5:

Given that:

AC = 4x - 12

AB = x

BC = 2x + 3

AB + BC = AC

x + (2x + 3) = 4x - 12

Combine like terms:

3x + 3 = 4x - 12

Add 12 on both sides of the equation:

3x + 3 + 12 = 4x - 12 + 12

3x + 15 = 4x

Subtract 3x from both sides of the equation:

3x - 3x + 15 = 4x - 3x

15 = x

Check if AB = x is valid by plugging in 15 to x values in the equation:

AB + BC = AC

15 + 2(15) + 3 = 4(15) - 12

15 + 30 + 3 = 60 - 12

48 = 48 (True statement)

5 0

2 years ago