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34kurt
4 years ago
6

Answer quickly 8x + 2y + 9 + 12x − 3

Mathematics
2 answers:
prohojiy [21]4 years ago
6 0
20x + 2y + 6 (simplified)
Blizzard [7]4 years ago
3 0

Since there is no answers to equate my answer with, 20x + 2y + 6 is the answer.

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Which pair of equations represent PARALLEL lines? A) y=2x and y = -1/2x B) y=2x and y = -1/2 C) y=2 and y=-2 D)y=2x=-2
Gennadij [26K]

Answer:

None

Step-by-step explanation:

Step 1: Write all the equations in the form y=mx+c, where m represents the gradient.

Notably, the equations are in that form already.

Step 2: Compare which equation have same value of m

In our case, none, hence no parallel lines

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3 years ago
7. Melissa bought 8 yards of string to make bracelets. She wants to cut the string in equal pieces that is 1/2 yard
ratelena [41]

Answer:

16 i think

Step by Step Explanation:

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3(2x-1 does this help you?
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3 years ago
On evaluating the expression 10(x - 20y) + 100x, the answer will be​
MArishka [77]

Answer:

110x -200y

Step-by-step explanation:

10(x - 20y) + 100x

Distribute

10x-200y +100x

Combine like terms

110x -200y

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3 years ago
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HELP PRECALC I DO NOT UNDERSTAND AT ALLLLL!!!!!!!!!!!!!!!!!!!!!!
Arlecino [84]

Answer:

  φ ≈ 1.19029 radians   (≈ 68.2°)

Step-by-step explanation:

There are simple formulas for A and φ in this conversion, but it can be instructive to see how they are derived.

We want to compare ...

  y(t) = Asin(ωt +φ)

to

  y(t) = Psin(ωt) +Qcos(ωt)

Using trig identities to expand the first equation, we have ...

  y(t) = Asin(ωt)cos(φ) +Acos(ωt)sin(φ)

Matching coefficients with the second equation, we have ...

  P = Acos(φ)

  Q = Asin(φ)

The ratio of these eliminates A and gives a relation for φ:

  Q/P = sin(φ)/cos(φ)

  Q/P = tan(φ)

  φ = arctan(Q/P) . . . . taking quadrant into account

__

We can also use our equations for P and Q to find A:

  P² +Q² = (Acos(φ))² +(Asin(φ))² = A²(cos(φ)² +sin(φ)²) = A²

  A = √(P² +Q²)

_____

Here, we want φ.

  φ = arctan(Q/P) = arctan(5/2)

  φ ≈ 1.19029 . . . radians

8 0
4 years ago
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