$\sum\limits_{t=1}^3\left(4\cdot\left(\dfrac{1}{2}\right)^{t-1}\right)=4\cdot\left(\dfrac{1}{2}\right)^{1-1}+4\cdot\left(\dfrac{1}{2}\right)^{2-1}+4\cdot\left(\dfrac{1}{2}\right)^{3-1}\\\\=4\cdot\left(\dfrac{1}{2}\right)^0+4\cdot\left(\dfrac{1}{2}\right)^1+4\cdot\left(\dfrac{1}{2}\right)^2=4\cdot1+4\cdot\dfrac{1}{2}+4\cdot\dfrac{1}{4}\\\\=4+2+1=7\\\\Answer:\ \boxed{D.\ 7}$

5 0

3 years ago

24:6 simplest please and thank you

kolbaska11 [484]

24:6 in simplest form is 4

6 0

3 years ago

Read 2 more answers

There is a sales tax of $6 on an item that costs $64 before tax. The sales tax on a second item is $8.25 . How much does the sec

bulgar [2K]

The second item would be $88 before tax since the tax rate is 9.375%

5 0

3 years ago