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Elina [12.6K]
2 years ago
13

Use the shell method to write and evaluate the definite integral that represents the volume of the solid generated by revolving

the plane region about the y-axis. y
Mathematics
1 answer:
faust18 [17]2 years ago
3 0

Answer:

Volume = \frac{384}{7}\pi

Step-by-step explanation:

Given (Missing Information):

y = x^\frac{3}{2}; y = 8; x=0

Required

Determine the volume

Using Shell Method:

V = 2\pi \int\limits^a_b {p(y)h(y)} \, dy

First solve for a and b.

y = x^\frac{3}{2} and y = 8

Substitute 8 for y

8 = x^\frac{3}{2}

Take 2/3 root of both sides

8^\frac{2}{3} = x^{\frac{3}{2}*\frac{2}{3}}

8^\frac{2}{3} = x

2^{3*\frac{2}{3}} = x

2^2 = x

4 =x

x = 4

This implies that:

a = 4

For x=0

This implies that:

b=0

So, we have:

V = 2\pi \int\limits^a_b {p(y)h(y)} \, dy

V = 2\pi \int\limits^4_0 {p(y)h(y)} \, dy

The volume of the solid becomes:

V = 2\pi \int\limits^4_0 {x(8 - x^{\frac{3}{2}}}) \, dx

Open bracket

V = 2\pi \int\limits^4_0 {8x - x.x^{\frac{3}{2}}} \, dx

V = 2\pi \int\limits^4_0 {8x - x^{\frac{2+3}{2}}} \, dx

V = 2\pi \int\limits^4_0 {8x - x^{\frac{5}{2}}} \, dx

Integrate

V = 2\pi  * [{\frac{8x^2}{2} - \frac{x^{1+\frac{5}{2}}}{1+\frac{5}{2}}]\vert^4_0

V = 2\pi  * [{4x^2 - \frac{x^{\frac{2+5}{2}}}{\frac{2+5}{2}}]\vert^4_0

V = 2\pi  * [{4x^2 - \frac{x^{\frac{7}{2}}}{\frac{7}{2}}]\vert^4_0

V = 2\pi  * [{4x^2 - \frac{2}{7}x^{\frac{7}{2}}]\vert^4_0

Substitute 4 and 0 for x

V = 2\pi  * ([{4*4^2 - \frac{2}{7}*4^{\frac{7}{2}}] - [{4*0^2 - \frac{2}{7}*0^{\frac{7}{2}}])

V = 2\pi  * ([{4*4^2 - \frac{2}{7}*4^{\frac{7}{2}}] - [0])

V = 2\pi  * [{4*4^2 - \frac{2}{7}*4^{\frac{7}{2}}]

V = 2\pi  * [{64 - \frac{2}{7}*2^2^{*\frac{7}{2}}]

V = 2\pi  * [{64 - \frac{2}{7}*2^7]

V = 2\pi  * [{64 - \frac{2}{7}*128]

V = 2\pi  * [{64 - \frac{2*128}{7}]

V = 2\pi  * [{64 - \frac{256}{7}]

Take LCM

V = 2\pi  * [\frac{64*7-256}{7}]

V = 2\pi  * [\frac{448-256}{7}]

V = 2\pi  * [\frac{192}{7}]

V = [\frac{2\pi  * 192}{7}]

V = \frac{\pi  * 384}{7}

V = \frac{384}{7}\pi

Hence, the required volume is:

Volume = \frac{384}{7}\pi

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