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4 years ago

WRITE THE PREDECESSOR OF THIS NUMBER 963,380

1 answer:

5 0

The predecessor of the number 963.380 is 963.379, because predecessor it means before the number ans sucessor it means after number.

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Solve the system of equations. please help asap! i appreciate it!

Natasha_Volkova [10]

Answer:

B. (-1, 2) and (4,7)

Step-by-step explanation:

Solve for the first variable in one of the equations, then substitute the result into the other equation.

5 0

3 years ago

Read 2 more answers

Find the equation, (f(x) = a(x-h)2+ k), for a parabola containing point (-1,0) and having (-3, 4) as a vertex. What is the stand

kirill115 [55]

$(h;\ k)\ -\ \text{the coordinates of the vertex}$

$\text{therefore we have:}\ f(x)=a(x+3)^2+4$

$\text{a parabola that passes through the point (-1; 0)}$

$\text{substitute the coordinates of the poin (-1; 0) to the equation}$

$(-1;\ 0)\to x=-1;\ y=0\\\\0=a(-1+3)^2+4\\\\0=a(2)^2+4\\\\0=4a+4\ \ \ |-4\\\\4a=-4\ \ \ |:4\\\\a=-1$

$f(x)=-(x+3)^2+4=-(x^2+2\cdot x\cdot3+3^2)+4=-(x^2+6x+9)+4\\\\=-x^2-6x-9+4=-x^2-6x-5$

5 0

3 years ago

Amy wants to estimate 11% of $9.11. what is a good estimate of the answer

arsen [322]

Amy can estimate with 10% instead, so she can just simply move the decimal point of $9.11 to the right, and so it will be estimated to more than 91 cents.

3 0

4 years ago

Convert 3/8 into decimal

saveliy_v [14]

Divide numerator (top number) by denominator (bottom number). 3 divided by 8. It’s 0.375

3 0

4 years ago

Read 2 more answers

The average watermelon weighs 8 lbs with a standard deviation of 1.5. Find the probability that a watermelon will weigh between

Andrew [12]

Answer:

The probability that a watermelon will weigh between 6.8 lbs and 9.3 lbs.

P(6.8 ≤X≤9.3) = 0.5932

Step-by-step explanation:

Step 1:-

by using normal distribution find the areas of given x₁ and x₂

Given The average watermelon weighs 8 lbs

μ = 8

standard deviation σ = 1.5

I) when x₁ = 6.8lbs and μ = 8 and σ = 1.5

$z_{1} = \frac{x_{1} -mean}{S.D} = \frac{6.8-8}{1.5} = - 0.8$

ii) when x₂ = 9.3 lbs and μ = 8 and σ = 1.5

$z_{2} = \frac{x_{2} -mean}{S.D} = \frac{9.3-8}{1.5} = 0.866>0$

<u>Step2</u>:-

The probability that a watermelon will weigh between 6.8 lbs and 9.3 lbs.

P(6.8 ≤X≤9.3) = A(z₂) - A(-z₁)

= A(0.866) - A(-0.8)

= A(0.866)+ A(0.8)

check below normal table

= 0.3051 + 0.2881

= 0.5932

<u>Conclusion</u>:-

The probability that a watermelon will weigh between 6.8 lbs and 9.3 lbs.

P(6.8 ≤X≤9.3) = 0.5932

7 0

3 years ago