Using derivatives, it is found that:
i) 
ii) 9 m/s.
iii) 
iv) 6 m/s².
v) 1 second.
<h3>What is the role of derivatives in the relation between acceleration, velocity and position?</h3>
- The velocity is the derivative of the position.
- The acceleration is the derivative of the velocity.
In this problem, the position is:
item i:
Velocity is the <u>derivative of the position</u>, hence:
Item ii:
The speed is of 9 m/s.
Item iii:
Derivative of the velocity, hence:
Item iv:
The acceleration is of 6 m/s².
Item v:
t for which a(t) = 0, hence:
Hence 1 second.
You can learn more about derivatives at brainly.com/question/14800626
Answer is (A). (X’ , Y’) = (x, y-6)
Answer:
a) r₁₂ = 104.36
In general, rₙ = arⁿ⁻¹
b)
- rabbit food consumed during the 10th year is approximately 832 pounds
- rabbit food consumed in total for the 1st through 10th years is approximately 5265 pounds
Step-by-step explanation:
Given that:
r1 = 30 and a farm grows by 12%
a = 30 and the common ratio r = 1.12
now
n r
1 30.00
2 33.60
3 37.63
4 42.15
5 47.21
6 52.87
7 59.21
8 66.32
9 74.28
10 83.19
11 93.18
12 104.36
Therefore r₁₂ = 104.36
In general, rₙ = arⁿ⁻¹
b)
if each rabbit consume 10 lbs of rabbit food each year
n r food consumed(lbs)
1 30.00 300
2 33.60 336
3 37.63 376
4 42.15 422
5 47.21 472
6 52.87 529
7 59.21 592
8 66.32 663
9 74.28 743
10 83.19 832
total 5265
Therefore, the rabbit food consumed during the 10th year is approximately 832 pounds
And the rabbit food consumed in total for the 1st through 10th years is approximately 5265 pounds
Answer:
G=7
Step-by-step explanation:
4(g-1)=24
4g-4=24
4g=28
g=7
Hi!
7 + (-3) = 7 - 3 = 4
The correct answer is C.) 4.
Hope this helps!
