Two angles are said to be complementary, if the sum of the measures of the to angles is equal to 90 degrees.
Thus, given that HFG is complementary to ACB, them mHFG + mACB = 90 degrees.
From the figure, given that the line from point F meats line CE at point P, then HFG = CFP.
But mCFE = 90 degrees and mCFE = mCFP + mPFE
Also PFE = DFH
Thus, mCFE = mCFP + mPFE = mHFG + mDFH = 90 degrees
Recall that mHFG + mACB = 90 degrees
Thus, mHFG + mACB = mHFG + mDFH
Therefore, mACB = mDFH.
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1 Answer. Suryin =) . 96√3 cm. Explanation: Area of regular hexagon : A=3√32a2. a is the side which is 8 cm. A=3√32(82). A=3√32(64). A= 192√32.
Slope of y = -⅓x + 3 is -⅓ (on comparing with m of y = mx + c)
As the required line is perpendicular to this, slope of the required line = - 1 / (-⅓) = 3
Equation:
=> y - y1 = m(x - x1)
=> y - 0 = (3)(x - (-2))
=> y = 3(x + 2)
=> 3x - y + 6 = 0
Answer:
3
Step-by-step explanation:
you go up 3 units and over to the left one unit
3/1 = 3
