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Rudiy27
3 years ago
13

Find the variables in the table.

Mathematics
1 answer:
Andru [333]3 years ago
6 0
4, 26 first is e second is f
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Rudiy27

a Anna drives her sisters at an a average of 60 mph and devive home

3 0
3 years ago
f(x) is a quadratic function with x-intercepts at (−1, 0) and (−3, 0). If the range of f(x) is [−4, [infinity]) and g(x) = 2x^2
iren2701 [21]

Answer with Step-by-step explanation:

We are given that function f(x) which is quadratic function.

x -intercept of function f(x) at (-1,0) and (-3,0)

x-Intercept of f means zeroes of f

x=-1 and x=-3

Range of f =[-4,\infty)

g(x)=2x^2+8x+6=2(x^2+4x+3)

g(x)=0

2(x^2+4x+3)=0

x^2+4x+3=0

x^2+3x+x+3=0

x(x+3)+1(x+3)=0

(x+1)(x+3)=0

x+1=0\implies x=-1

x+3=0\implies x=-3

Therefore, x-intercept of g(x) at (-1,0) and (-3,0).

Substitute x=-2

g(-2)=2(-2)^2+8(-2)+6=8-16+6=-2

g(x)=2(x^2+4x)+6

g(x)=2(x^2+2\times x\times 2+4-4)+6=2(x^2+2\times x\times 2+4)-8+6

g(x)=2(x+2)^2-2

By comparing with the equation of parabola

y=a(x-h)^2+k

Where vertex=(h,k)

We get vertex of g(x)=(-2,-2)

Range of g(x)=[-2,\infty)

Zeroes of f and g are same .

But range of f and g are different.

Range of f contains -3 and -4 but range of g does not contain -3 and -4.

f and g are both quadratic functions.

3 0
3 years ago
( YOU’LL GET MARKED BRAINLIEST !! )
Mariulka [41]

Answer:

1/4

Step-by-step explanation:

The answer to this question is the amount of blue gummy bears over the total amount of gummy bears. This is 15/60 or 1/4.

4 0
3 years ago
Read 2 more answers
Heloo can you guys help me with this question thank you
zysi [14]
He bought 2.5 pounds of apples on monday, then another 1.2 pounds on tuesday. In total, he bought 2.5+1.2 = 3.7 pounds of apples.

Multiply this with the cost per pound (2.20)
3.7*2.20 = 8.14

Answer: Choice C) $8.14
8 0
3 years ago
Read 2 more answers
Logx(8x-3)-logx 4=2<br> please help ill give you everything i have !!
Gelneren [198K]
Logx (8x-3) - logx 4 = 2
logx [(8x-3)/4] = 2
x^2=(8x-3)/4
4x^2=4(8x-3)/4
4x^2=8x-3
4x^2-8x+3=8x-3-8x+3
4x^2-8x+3=0
4(4x^2-8x+3=0)
(4^2)(x^2)-8(4x)+12=0
(4x)^2-8(4x)+12=0
(4x-2)(4x-6)=0
2(4x/2-2/2)2(4x/2-6/2)=0
4(2x-1)(2x-3)=0
4(2x-1)(2x-3)/4=0/4
(2x-1)(2x-3)=0
Two options:
1) 2x-1=0
2x-1+1=0+1
2x=1
2x/2=1/2
x=1/2

2) 2x-3=0
2x-3+3=0+3
2x=3
2x/2=3/2
x=3/2

Answer: Two solutions: x=1/2 and x=3/2
6 0
3 years ago
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