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3 years ago

What is 4×7 Please answer

Mathematics

2 answers:

stealth61 [152]3 years ago

5 0

4 x 7= 28

BTW no calculator. Did it in my head. Hope this helps!

Sergio039 [100]3 years ago

3 0

4 times 7= 28. or 7 times 4 =28.

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WITCHER [35]

Answer:

2.2360679775

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Can anyone please help me!?<br> dont answer nonsense for points plz or i will report

kramer

See explanations

Step-by-step explanation:

Choosing the product of power property,when you multiply exponentials with the same base , you add their exponents.

This is represented as :

$(x^a)*(x^b)=(x^{a+b)}$

This property is true in that ;

where you have x³ × x³ , x³ is x*x*x and the other x³ is x*x*x .Adding the xs will give x⁶ which is similar to 3+3=6 xs

A numerical example could be;

$x^2+x^3=x^{2+3} =x^5$

Learn More

Properties of exponential functions :brainly.com/question/8742222

Keywords : properties, exponents, numerical expression

#LearnwithBrainly

3 0

3 years ago

Expand and simplify 2/5(p+15)-1/3(9+6p)+4/5p

Pavlova-9 [17]

2/5p+6-3-2p+4/5p
-2p+6/5p+6-3+4
-10/5p+6/5p+3+4
-4/5p+7
-0.8p+7

7 0

3 years ago

Sixteen more than twice a number,m, is 36. write an equation and solve to find the number.

Dimas [21]

32m=36
m=36/32
m=9/8
that's the correct answer

3 0

3 years ago

A statistician uses Chebyshev's Theorem to estimate that at least 15 % of a population lies between the values 9 and 20. Use thi

rjkz [21]

Answer:

\mu = 14.5\\

\sigma = 5.071\\

k = 1.084

Step-by-step explanation:

given that a statistician uses Chebyshev's Theorem to estimate that at least 15 % of a population lies between the values 9 and 20.

i.e. his findings with respect to probability are

$P(9$

Recall Chebyshev's inequality that

$P(|X-\mu |\geq k\sigma )\leq {\frac {1}{k^{2}}}\\P(|X-\mu |\leq k\sigma )\geq 1-{\frac {1}{k^{2}}}\\$

Comparing with the Ii equation which is appropriate here we find that

$\mu =14.5$

Next what we find is

$k\sigma = 5.5\\1-\frac{1}{k^2} =0.15\\\frac{1}{k^2}=0.85\\k=1.084\\1.084 (\sigma) = 5.5\\\sigma = 5.071$

Thus from the given information we find that

$\mu = 14.5\\\sigma = 5.071\\k = 1.084$

5 0

3 years ago