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lorasvet [3.4K]
3 years ago
7

What is 6.16×10^6 in standard form?

Mathematics
2 answers:
OleMash [197]3 years ago
4 0
Your answer is  6,160,000 my friend
Bas_tet [7]3 years ago
4 0

6.16 x 10^6 = 6,160,000

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PLEASE RESPOND! !!
cestrela7 [59]

Answer:

36/132

Step-by-step explanation:

36/132, .27, 27%...

6 0
3 years ago
Write an equation then solve it
umka2103 [35]
2x+54= 3x
x=54
teh answer is 54
7 0
3 years ago
Read 2 more answers
The value of a new truck decreases exponentially at a rate of 4.8% per year. If the purchase price of the new cars $42,000, how
Usimov [2.4K]

The worth of the car after it is paid off 5 years later given the rate of exponential depreciation is $32,842.34.

<h3>What is the worth of the car?</h3>

When the car declines in value, it means that the car is depreciating. The formula that can be used to determine the value of the car with the depreciationn rate is:

FV = P (1 - r)^n

  • FV = Future value
  • P = Present value
  • R = rate of decline
  • N = number of years

$42,000 x (1 - 0.048)^5 = $32,842.34

To learn more about future value, please check: brainly.com/question/18760477

7 0
2 years ago
Is the given point interior , exterior, or on the circle k (x+2)2 + (y-3)2 =18 P (8,4)
Mnenie [13.5K]
One way would be to find the distance from the point to the center of the circle and compare it to the radius

for
(x-h)^2+(y-k)^2=r^2
the center is (h,k) and the radius is r

and the distance formula is
distance between (x_1,y_1) and (x_2,y_2) is
D=\sqrt{(x_1-x_2)^2+(y_1-y_2)^2}


r=radius
D=distance form (8,4) to center

if r>D, then (8,4) is inside the circle
if r=D, then (8,4) is on the circle
if r<D, then (8,4) is outside the circle


so
(x+2)^2+(y-3)^2=18
(x-(-2))^2+(y-3)^2=(\sqrt{18})^2
(x-(-2))^2+(y-3)^2=(3\sqrt{2})^2

the radius is 3\sqrt{2}
center is (-2,3)

find distance between (8,4) and (-2,3)

D=\sqrt{(8-(-2))^2+(4-3)^2}
D=\sqrt{(8+2)^2+(1)^2}
D=\sqrt{10^2+1}
D=\sqrt{100+1}
D=\sqrt{101}




r=3\sqrt{2}≈4.2
D=\sqrt{101}≈10.04

do r<D

(8,4) is outside the circle

6 0
3 years ago
The position function for the movement of a particle is given by s=(t^3+1)^2 where s is measure in feet and t is measured in sec
Ray Of Light [21]

Answer:

The position of particle at 1 second is 4 feet.            

Step-by-step explanation:

We are given the following in the question:

s(t)=(t^3+1)^2

where s is a position function and measure in feet and t is measured in seconds.

We have to evaluate the position at 1 second.

Putting t = 1 in the position function, we get.

s(1)=((1)^3+1)^2\\s(1) = 4

Thus, the position of particle at 1 second is 4 feet.

3 0
3 years ago
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