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3 years ago

10

Suppose the volume of a cylinder is 169.65 ft cubes and the height is twice the radius what is the radius of the cylinder.

1 answer:

Delvig [45]3 years ago

3 0

Answer:

The radius of the cylinder is $r=3\ ft$

Step-by-step explanation:

we know that

The volume of the cylinder is equal to

$V=\pi r^{2} h$

we have

$V=169.65\ ft^{3}$

$h=2r\ ft$

assume

$\pi=3.14$

substitute the values and solve for r

$169.65=(3.14)r^{2} (2r)$

$169.65=(6.28)r^{3}$

$r^{3}=169.65/(6.28)$

$r=3\ ft$

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Step-by-step explanation:

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Then, the mean of the distribution of sample mean is given by,

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And the standard deviation of the distribution of sample mean is given by,

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(a)

The standard error is the standard deviation of the sampling distribution of sample mean.

Compute the standard deviation of the sampling distribution of sample mean as follows:

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(b)

Compute the probability that the sample mean is between $3.78 and $3.86 as follows:

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Thus, the probability that the sample mean is between $3.78 and $3.86 is 0.5587.

(c)

If the difference between the sample mean and the population mean is less than $0.01 then:

$\bar X-\mu_{\bar x}$

Compute the value of $P(\bar X$ as follows:

$P(\bar X$

$=P(Z$

Thus, the probability that the difference between the sample mean and the population mean is less than $0.01 is 0.5754.

(d)

Compute the probability that the sample mean is greater than $3.92 as follows:

$P(\bar X>3.92)=P(\frac{\bar X-\mu_{\bar x}}{\sigma_{\bar x}}>\frac{3.92-3.82}{0.052})$

$=P(Z$

Thus, the likelihood that the sample mean is greater than $3.92 is 0.9726.

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