Question

Suppose the volume of a cylinder is 169.65 ft cubes and the height is twice the radius what is the radius of the cylinder.

Answer 1

Answer:

The radius of the cylinder is $r=3\ ft$

Step-by-step explanation:

we know that

The volume of the cylinder is equal to

$V=\pi r^{2} h$

we have

$V=169.65\ ft^{3}$

$h=2r\ ft$

assume

$\pi=3.14$

substitute the values and solve for r

$169.65=(3.14)r^{2} (2r)$

$169.65=(6.28)r^{3}$

$r^{3}=169.65/(6.28)$

$r=3\ ft$