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ozzi
3 years ago
10

Suppose the volume of a cylinder is 169.65 ft cubes and the height is twice the radius what is the radius of the cylinder.

Mathematics
1 answer:
Delvig [45]3 years ago
3 0

Answer:

The radius of the cylinder is r=3\ ft

Step-by-step explanation:

we know that

The volume of the cylinder is equal to

V=\pi r^{2} h

we have

V=169.65\ ft^{3}

h=2r\ ft

assume

\pi=3.14

substitute the values and solve for r

169.65=(3.14)r^{2} (2r)

169.65=(6.28)r^{3}

r^{3}=169.65/(6.28)

r=3\ ft

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Why was Florence such an ideal city for artistic expression? a. Most artists were born in Florence. b. Florence promoted economi
iren2701 [21]

Answer:

B. Florence promoted economic and social freedom

Step-by-step explanation:

Edgenuity 2020

4 0
3 years ago
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ANSWER QUICK!!! IM TAKING A TEST AND I WILL MARK BRAINLIEST!!!
gtnhenbr [62]

Answer:

C = 5Q

Step-by-step explanation:

C = Length of Cloth in Meters (C)

Q = Number of Quilts Made (Q)

C = 5Q

Change C for the numbers under (Length of Cloth in Meters (C))
Nad change Q for the numbers under (Number of Quilts Made (Q))

So the new equations would be:

0 = 5(0) --------->  0 = 0

5 = 5(1) ---------> 5 = 5

10 = 5(2) ---------> 10 = 10

15 = 5(3) ---------> 15 = 15

20 = 5(4) ---------> 20 = 20

25 = 5(5) ---------> 25 = 25

So the only option that amkes sense is (C = 5Q)

3 0
3 years ago
A newspaper published an article about a study in which researchers subjected laboratory gloves to stress. Among 225 vinyl? glov
romanna [79]

Answer:

a)

H₀: ρ₁ ≤ ρ₂

H₁: ρ₁ > ρ₂

b)

Z= \frac{('p_{1} - 'p_{2}) - (p_{1} - p_{2})}{\sqrt{'p(1-'p)[\frac{1}{n_1} + \frac{1}{n_2} ]} } ≈ N(0;1)

c)

p-value < .00001

d)

Reject the null hypothesis.

The population proportion vinyl gloves that leak viruses is greater than the population proportion of latex gloves that leak viruses.

Step-by-step explanation:

Hello!

The objective is to test if the population proportion of vinyl gloves that leak viruses (population 1) is greater then the population proportion of latex gloves that leak viruses (population 2).

Sample 1 (Vinyl)

n₁= 225

Sample proportion 'ρ₁= 0.60

Sample 2 (Latex)

n₂= 225

Sample proportion 'ρ₂= 0.09

Pooled proportion: 'ρ= (x₁+x₂)/(n₁+n₂)= ( 'ρ₁ + 'ρ₂)/2= (0.60 + 0.09)/2= 0.345 ≅0.35

The hypothesis is:

H₀: ρ₁ ≤ ρ₂

H₁: ρ₁ > ρ₂

α: 0.05

The statistic to use is a pooled Z

Z= \frac{('p_{1} - 'p_{2}) - (p_{1} - p_{2})}{\sqrt{'p(1-'p)[\frac{1}{n_1} + \frac{1}{n_2} ]} } ≈ N(0;1)

The critical region is one-tailed to the right (positive), the critical value is:

Z_{1-\alpha } = Z_{0.95} = 1.64

If Z ≥ 1.64, you will reject the null hypothesis.

If Z < 1.64, you will not reject the null hypothesis.

Z= \frac{(0.6 - 0.09) - (0}{\sqrt{0.35(1-0.35)[\frac{1}{225} + \frac{1}{225} ]} } = 11.34

Since the calculated Z- value is greater than the critical value, the decision is to reject the null hypothesis. The population proportion vinyl gloves that leak viruses is greater than the population proportion of latex gloves that leak viruses.

P-value approach:

p-value < .00001

If you compare with the level of signification, you reach the same decision.

I hope it helps!

8 0
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\ln(b^x) = M-\ln(a)

Use the property \ln(a^b) = b\ln(a) to rewrite the equation as

x\ln(b) = M-\ln(a)

Divide both sides by \ln(b)

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Alternative strategy:

Consider both sides as exponents of e:

e^{\ln(ab^x)} = e^M

Use e^{\ln(x)} = x to write

ab^x = e^M

Divide both sides by a:

b^x = \dfrac{e^M}{a}

Consider the logarithm base b of both sides:

x = \log_b\left(\dfrac{e^M}{a}\right)

The two numbers are the same: you can check it using the rule for changing the base of logarithms

7 0
3 years ago
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Elan Coil [88]
3 is the correct answer, you could always check your work by dividing 0.000027 by 3 which would get you 0.000009. I hope this helped =)
3 0
3 years ago
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