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3 years ago

What is (f - g)(x)? f (x) = 24 – 22 + 9 9(2) = 23 + 3x2 + 12 (f - g)(x) = ???

Mathematics

1 answer:

bija089 [108]3 years ago

7 0

Answer:

(f - g)(x) = x^4 - x^3 - 4x^2 - 3

Step-by-step explanation:

Subtract g(x)=x^3 + 3x^2 + 12 from f(x)= x^4 - x^2 + 9

First, take the negative of every term (including the label g(x) ) of g(x), obtaining -g(x) = -x^3 - 3x^2 - 12.

Now combine this result with f(x):

f(x)= x^4 - 0x^3 - x^2 + 9

-g(x) = - 1x^3 - 3x^2 - 12

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(f - g)(x) = x^4 - x^3 - 4x^2 - 3

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A ball is thrown vertically upward from the top of a building 64 feet tall with an initial velocity of 48 feet per second. The d

Klio2033 [76]

Answer:

a) t = 4 secs

b) t = 3 secs

Step-by-step explanation:

h = 64 ft

Initial velocity = 48 ft/s

S = 64 + 48t - 16t^2

a) Set S = 0 and solve for t

0 = 64 + 48t - 16t^2

Divide through by 16

0 = 4 + 3t - t^2

t^2 - 3t - 4 = 0

t^2 - 4t + t - 4 = 0

t(t - 4) + 1(t - 4) = 0

(t + 1) (t - 4) = 0

t + 1 = 0 or t - 4 = 0

t = -1 or t = 4

t = {-1,4}

t = 4 seconds

b) Set S = 64 and solve for t

64 = 64 + 48t - 16t^2

64 - 64 = 48t - 16t^2

0 = 48t - 16t^2

Divide through by 16

0 = 3t - t^2

t^2 - 3t = 0

t(t - 3) = 0

t = 0 or t-3 = 0

t = 0 or t = 3

t = {0,3}

t = 3 secs

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