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3 years ago

How do I get my answer to this question

Mathematics

2 answers:

Marizza181 [45]3 years ago

8 0

The answer is 268 because you 2144÷8

stich3 [128]3 years ago

8 0

Lovin Lemon: 4 gallons for $24 = $6/gallon

Sweet and Sour: 8 quarts for $16 = 2 gallons for $16 = $8/gallon

Answer: Sweet and Sour has the higher unit price

2144 miles in 8 hours

2144/8 = 268 miles per hour

Answer a: 268

560 miles / 268 mph = 140/67 hours = 2.08955... hours

Answer: 2.09 hours

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Round 14494 to the nearest thousand feet

klasskru [66]

14,000 because 494 would round down since it is not above 500.

7 0

3 years ago

May and Ellie collected data for 75 graphs, recording whether the graphs were increasing or decreasing, and whether or not they

m_a_m_a [10]

Answer:

What are you gonna do is across the x

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

Can someone please explain expanded form with this number 15,409

Anarel [89]

The expanded form of 15,409 would be 15,000 + 400 + 9.

Your 15 would alone be 15,000. The 409 is turned into zeros.
For 409, take the 9 off of the end and keep it by itself, and then add a zero in replace for the 9, which makes 400.
The 9 should come in at the last part as it is the last number.

Add them all together and you should get <span>15,000 + 400 + 9.</span>

3 0

3 years ago

According to one cosmological theory, there were equal amounts of the two uranium isotopes 235U and 238U at the creation of the

FromTheMoon [43]

Answer:

6 billion years.

Step-by-step explanation:

According to the decay law, the amount of the radioactive substance that decays is proportional to each instant to the amount of substance present. Let $P(t)$ be the amount of $^{235}U$ and $Q(t)$ be the amount of $^{238}U$ after $t$ years.

Then, we obtain two differential equations

$\frac{dP}{dt} = -k_1P \quad \frac{dQ}{dt} = -k_2Q$

where $k_1$ and $k_2$ are proportionality constants and the minus signs denotes decay.

Rearranging terms in the equations gives

$\frac{dP}{P} = -k_1dt \quad \frac{dQ}{Q} = -k_2dt$

Now, the variables are separated, $P$ and $Q$ appear only on the left, and $t$ appears only on the right, so that we can integrate both sides.

$\int \frac{dP}{P} = -k_1 \int dt \quad \int \frac{dQ}{Q} = -k_2\int dt$

which yields

$\ln |P| = -k_1t + c_1 \quad \ln |Q| = -k_2t + c_2$ ,

where $c_1$ and $c_2$ are constants of integration.

By taking exponents, we obtain

$e^{\ln |P|} = e^{-k_1t + c_1} \quad e^{\ln |Q|} = e^{-k_12t + c_2}$

Hence,

$P = C_1e^{-k_1t} \quad Q = C_2e^{-k_2t}$ ,

where $C_1 := \pm e^{c_1}$ and $C_2 := \pm e^{c_2}$ .

Since the amounts of the uranium isotopes were the same initially, we obtain the initial condition

$P(0) = Q(0) = C$

Substituting 0 for $P$ in the general solution gives

$C = P(0) = C_1 e^0 \implies C= C_1$

Similarly, we obtain $C = C_2$ and

$P = Ce^{-k_1t} \quad Q = Ce^{-k_2t}$

The relation between the decay constant $k$ and the half-life is given by

$\tau = \frac{\ln 2}{k}$

We can use this fact to determine the numeric values of the decay constants $k_1$ and $k_2$ . Thus,

$4.51 \times 10^9 = \frac{\ln 2}{k_1} \implies k_1 = \frac{\ln 2}{4.51 \times 10^9}$

and

$7.10 \times 10^8 = \frac{\ln 2}{k_2} \implies k_2 = \frac{\ln 2}{7.10 \times 10^8}$

Therefore,

$P = Ce^{-\frac{\ln 2}{4.51 \times 10^9}t} \quad Q = Ce^{-k_2 = \frac{\ln 2}{7.10 \times 10^8}t}$

We have that

$\frac{P(t)}{Q(t)} = 137.7$

Hence,

$\frac{Ce^{-\frac{\ln 2}{4.51 \times 10^9}t} }{Ce^{-k_2 = \frac{\ln 2}{7.10 \times 10^8}t}} = 137.7$

Solving for $t$ yields $t \approx 6 \times 10^9$ , which means that the age of the universe is about 6 billion years.

5 0

3 years ago

Sven has $1 and a dime in his pile. Dayna has 11 dimes in her pile. If Sven gives Dayna $1 and Dayna gives Sven 10 dimes, will t

viva [34]

Answer:

Yes

Step-by-step explanation:

Because a dollar and a dime and 11 dimes are equal in value ($1.10)

And they exchange 1 dollar and 10 dimes which is also the same amount. So they will be the same.

8 0

2 years ago