1. 2x³ - 11x² + 13x - 21 ÷ x - 3
x - 3 = 0 ⇒ x = 3
3 | 2 -11 13 -21
<u>| ↓ 6 -15 -6</u>
2 -5 -2 -27
1. Answer: 2x² - 5x - 2 - 
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2. 3x³ + 7x² - 13x + 10 ÷ x + 2
x + 2 = 0 ⇒ x = -2
-2 | 3 7 -13 10
<u>| ↓ -6 -2 30</u>
3 1 -15 40
2. Answer: 3x² + x - 15 + 
3. 2x³ + 13x² - 21x + 9 ÷ x - 1
x - 1 = 0 ⇒ x = 1
1 | 2 13 -21 9
<u>| ↓ 2 15 -6</u>
2 15 -6 3
3. Answer: 2x² + 15x - 6 + 
4. 7x³ + 0x² - 8x + 16 ÷ x - 2
x - 2 = 0 ⇒ x = 2
2 | 7 0 -8 16
<u>| ↓ 14 28 40</u>
7 14 20 56
4. Answer: 7x² + 14x + 20 + 
5. 8x⁴ - 14x³ - 71x² - 10x + 24 ÷ x - 4
x - 4 = 0 ⇒ x = 4
4 | 8 -14 -71 -10 24
<u>| ↓ 32 72 4 -24 </u>
8 18 1 -6 0
5. Answer: 8x³ + 18x² + x - 6
Answer:
B. csc²(x)
Step-by-step explanation:
You can use the relations ...
sec(x) = 1/cos(x)
csc(x) = 1/sin(x)
cot(x) = cos(x)/sin(x)
to replace the functions in your expression. Then you have ...
sec²(x)·cot²(x) = (1/cos(x)·cos(x)/sin(x))² = (1/sin(x))² = csc²(x)
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Alternate solution
You can also use the relation
cot(x) = csc(x)/sec(x)
Then ...
(sec(x)·cot(x))² = (sec(x)·csc(x)/sec(x))² = csc²(x)
The answer is (X=3). You could have did 4-1 which is 3.
Answer:
Option C
Step-by-step explanation:
From the picture attached,
m∠ABC = 40° [Given]
Since, measure of the intercepted arc is double of the measure of the inscribed angle.
Therefore, m(arc AC) = 2(m∠ABC)
m(arc AC) = 2(40°)
= 80°
m(arc FB) = 115° [Given]
By applying theorem of the angles formed by the chords inside a circle,
m∠2 = 
= 
= 97.5°
m∠1 + m∠2 = 180° [Linear pair of angles are supplementary]
m∠1 + 97.5° = 180°
m∠1 = 180° - 97.5°
= 82.5°
Option C is the answer.
