Number of ways the second grade students can sit on the first row is 5! = 5P5
Number of ways 15 first grade students can sit in the remaining 20 seats is 20P15
Therefore, required number of ways is 5P5 * 20P15. (option B)
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Answer:
k=(5x+6)/(3x+6) and k<3/5
Step-by-step explanation:
- 3k(x+2)+2 = 5x+8
- 3k(x+2)=5x+6
- 3k=(5x+6)/(x+2)
- k=(5x+6)/(3x+6)
it is solved for k
and considering the condition for x<3:
- 3k(x+2)+2 = 5x+8
- 3kx+6k=5x+6
- (5-3k)x=6k-6
- x= (6k-6)/(5-3k)
- x<3 ⇒ (6k-6)/(5-3k)<3 ⇒ 6k-6<15-9k ⇒ 15k<9 ⇒ k<9/15 ⇒ k<3/5
So,
k=(5x+6)/(3x+6) and k<3/5
Answer:
Step-by-step explanation:
step 1
Find the measure of angle EFD
In this problem I will assume that ABCD is a parallelogram
In a parallelogram opposite angles are congruent and consecutive angles are supplementary
so
--- > given problem
Remember that the sum of the interior angles in any triangle must be equal to 180 degrees
so
In the triangle EFD
substitute the given values
step 2
Find the measure of angle EFB
we know that
---> by supplementary angles
we have
substitute
step 3
Find the value of x
Remember that the sum of the interior angles in any triangle must be equal to 180 degrees
so
In the triangle EBF
we have
substitute
solve for x
Combine like terms

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