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3 years ago

This is precents what is 20% of 50

Mathematics

2 answers:

11111nata11111 [884]3 years ago

8 0

The answer is ten hope this helps :-)

tekilochka [14]3 years ago

8 0

20% of 50=10 hope dis helps

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49x^2=-21x-2 quadratic functions

lara [203]

Answer: 49x^2=-21x-2 quadratic functions -1/7and -2/7

Step-by-step explanation:

Quadratic function:

In elementary algebra, the quadratic formula is a formula that provides the solution to a quadratic equation. There are other ways of solving a quadratic equation instead of using the quadratic formula, such as factoring, completing the square, graphing and others.

Move terms to the left side

49 $x^{2}$ =-21x-2

49 $x^{2}$ -(-21x-2) =0

Distribute

49 $x^{2}$ -(-21x-2) =0

49 $x^{2}$ +21x+2=0

Use the quadratic formula

x=(-b±√ $b^{2}$ -4ac ) / 2a

Once in standard form, identify a, b, and c from the original equation and plug them into the quadratic formula.

49 $x^{2}$ +21x+2=0

let, a=49

b=21

c=2

Replace with values in this equation

X=(-b±√ $b^{2}$ -4ac ) / 2a

Simplify

Evaluate the exponent

Multiply the numbers

Subtract the numbers

Evaluate the square root

Multiply the numbers

x=(-21±7) /98

Separate the equations

To solve for the unknown variable, separate into two equations: one with a plus and the other with a minus.Separate

x=(-21+7) /98

x=(-21-7) /98

Solve

Rearrange and isolate the variable to find each solution

x=-1/7

x=-2/7

Learn more about area here https://brainly.in/question/5597925

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3 0

1 year ago

Please help me I am very confused.

garri49 [273]

1/2
When you put a square root into exponential form, the square root turns into an exponential fraction. Since the square root is 2, our fraction would be 1/2

If our root was a cube root, our exponent would be 1/3, etc.

7 0

3 years ago

Read 2 more answers

Consider functions f and g.1 + 12f(1) = 12 + 4. – 12for * # 2 and 7 -64.2 – 16. + 1641 +48for a # -12 Which expression is equal

lisabon 2012 [21]

Given the following functions below,

$\begin{gathered} f(x)=\frac{x+12}{x^2+4x-12}\text{ and} \\ g(x)=\frac{4x^2-16x+16}{4x+48} \end{gathered}$

Factorising the denominators of both functions,

Factorising the denominator of f(x),

$\begin{gathered} f(x)=\frac{x+12}{x^2+4x-12}=\frac{x+12}{x^2+6x-2x-12}=\frac{x+12}{x(x+6)-2(x+6)}=\frac{x+12}{(x-2)(x+6)} \\ f(x)=\frac{x+12}{(x-2)(x+6)} \end{gathered}$

Factorising the denominator of g(x),

$\begin{gathered} g(x)=\frac{4x^2-16x+16}{4x+48}=\frac{4(x^2-4x+4)}{4(x+12)} \\ \text{Cancel out 4 from both numerator and denominator} \\ g(x)=\frac{x^2-4x+4}{x+12}=\frac{x^2-2x-2x+4}{x+12}=\frac{x(x-2)-2(x-2)}{x+12}=\frac{(x-2)^2}{x+12} \\ g(x)=\frac{(x-2)^2}{x+12} \end{gathered}$

Multiplying both functions,

$undefined$

4 0

1 year ago

Consider this algebraic expression: –3x + x + 5 Use the algebra tiles to model the expression.

luda_lava [24]

For this case, we have the following expression:

$-3x + x + 5$

We simplify the expression:

If we add similar terms, taking into account that different signs are subtracted and the sign of the greater one is placed, we have that $-3x + x = -2x$