2^3 * 2^-5 = 2^(3 + (-5) = 2^(3 - 5) = 2^-2
Answer:
Step-by-step explanation:
hello :
the system is : x+ y =4 ...(*)
2x - y = -1...(**)
add(*) and (**) : 3x=3 so : x=1
put this value into (*) : 1+y=4 so : y=3
one solution : (1 , 3)
ASSUMPTION: Since we are talking about fractions it looks like you have to simplify it. Again, its still a guess so Id assume..
16/12 = 4/3.. So It should be <em>h = 2 </em>
Answer:
Solution Let E1 be the event that coin 1 is selected and E2 the event that coin 2 is selected. Let F be the event that exactly 7 of the 10 flips lands on heads, let G be the event that the fist flip is heads.
