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3 years ago

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When coin 1 is flipped, it lands on heads with probability .4; when coin 2 is flipped, it lands on heads with probability .7. On

e of these coins is randomly chosen and flipped 10 times. (a) what is the probability that exactly 7 of the 10 flips lands on heads? (b) Given that the first of these 10 flips lands heads, what is the conditional probability that exactly 7 of these 10 flips lands on heads?

1 answer:

I am Lyosha [343]3 years ago

6 0

Answer:

Solution Let E1 be the event that coin 1 is selected and E2 the event that coin 2 is selected. Let F be the event that exactly 7 of the 10 flips lands on heads, let G be the event that the fist flip is heads.

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How to find the area of a semi-circle PLEASE HELP ME

GREYUIT [131]

D'ou know the area of a circle?

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3 years ago

Consider the sequence defined recursively by do = 0, an = an-1 + 3n – 1. a) Write out the first 5 terms of this sequence,

creativ13 [48]

Answer:

The first 5 terms of the sequence is 2,7,15,26,40.

Step-by-step explanation:

Given : Consider the sequence defined recursively by $a_0=0$ $a_n=a_{n-1}+3n-1$

To find : Write out the first 5 terms of this sequence ?

Solution :

$a_n=a_{n-1}+3n-1$ and $a_0=0$

The first five terms in the sequence is at n=1,2,3,4,5

For n=1,

$a_1=a_{1-1}+3(1)-1$

$a_1=a_{0}+3-1$

$a_1=0+2$

$a_1=2$

For n=2,

$a_2=a_{2-1}+3(2)-1$

$a_2=a_{1}+6-1$

$a_2=2+5$

$a_2=7$

For n=3,

$a_3=a_{3-1}+3(3)-1$

$a_3=a_{2}+9-1$

$a_3=7+8$

$a_3=15$

For n=4,

$a_4=a_{4-1}+3(4)-1$

$a_4=a_{3}+12-1$

$a_4=15+11$

$a_4=26$

For n=5,

$a_5=a_{5-1}+3(5)-1$

$a_5=a_{4}+15-1$

$a_5=26+14$

$a_5=40$

The first 5 terms of the sequence is 2,7,15,26,40.

5 0

3 years ago

I really don’t know how to do this at all , help

klasskru [66]

Answer:

Plot -11 on the tick mark directly to the left of -10.

Step-by-step explanation:

Hope this helps!

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5 0

2 years ago

Read 2 more answers

The volume of the cube below is 250.047 m^3. The side length could be between which sets of numbers below?

Eva8 [605]

Step-by-step explanation:

The volume of the cube below is 250.047 m^3. The side length could be between which sets of numbers below?

A. 4 cm and 5cm

B 5cm and 6 cm

C. 6 cm and 7 cm

D. 7 cm and 8 cm

ans.C

4 0

2 years ago

poizon [28]

9514 1404 393

Answer:

$1790.99

Step-by-step explanation:

<u>Given</u>:

$1625 is invested at an annual rate of 1.95% compounded quarterly for 5 years

<u>Find</u>:

the ending balance

<u>Solution</u>:

The compound interest formula applies.

FV = P(1 +r/n)^(nt) . . . Principal P at rate r for t years, compounded n per year

FV = $1625(1 +0.0195/4)^(4·5) = $1625(1.004875^20) ≈ $1790.99

The account ending balance would be $1790.99.

8 0

3 years ago