6
24% = 
multiply 25 by this fraction
25 ×
=
= 6
Answer:
Widgets should be sold by $38.88 to maximize the profit.
Step-by-step explanation:
Vertex of a quadratic function:
Suppose we have a quadratic function in the following format:

It's vertex is the point 
In which


Where

If a<0, the vertex is a maximum point, that is, the maximum value happens at
, and it's value is
.
In this question:
The profit is given by:

Which is a quadratic function with 
The maximum profit happens at the x of the vertex. Thus

Widgets should be sold by $38.88 to maximize the profit.
Hello!
The letter D is in the place for the upper quartile
To find this you have to find the median of the data
List the numbers from least to greatest
12, 18, 34, 55, 59, 68, 80, 80
The medians are 55 and 59
To get the median we take the average of these numbers
55 + 59 = 114
114 / 2 = 57
The median is 57
To find the upper quartile you find the median of the numbers higher than 57
List the numbers that are higher than 57 in the data
59, 68, 80, 80
Take the average of 68 and 80
68 + 80 = 148
148/2 = 74
The answer is 74
Hope this helps!
Aritmetic increases by the same number
geometric has 1 number that each term is multiplied by to get the next term
4 to 9 is 5
9 to 13 is 4
not same difference
9/4=13/9?
81/36=52/36?
no
neither aritmetic nor geometric
After 12 hours the pound would have 720 pounds of algae.