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Leona [35]
3 years ago
13

How many different license plates can be produced using 4 digits and 2 letters if the first digit cannot be the number 0 and the

letters o and I cannot be used at letters
Mathematics
1 answer:
Rainbow [258]3 years ago
3 0
650 letter permutations * 5040 numbers permutations = total licence number possible = 3,276,000
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John Gray bought a basic car for $8,250.00, with options that cost $324.00. There's a 6% sales tax in his state and a combined $
Crank
Cost of the basic car bought by John Gray = $8250
Optional cost incurred after buying = $324
Total cost before tax = 8250 + 324
                                 = $8574 
Percentage of sales tax incurred = 6%
Amount of sales tax charged = (6/100) * 8574
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License and registration fees paid = $50
John's total cost = 8250 + 324 + 514.44 + 50
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From the above deduction, it can be easily concluded that the correct option among all the options that are given in the question is the first option or option "A".
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Craig = p points
Marla = 2p points
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kolbaska11 [484]
Negative plus a negative is always positive. positive plus a positive is a positive. but if you have an positive plus a negative whatever sign has the bigger number thats the sign you'll use.  
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I need help with this equation 20 points help quick
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Answer:

\boxed{y=|\frac{1}{2}x  - \frac{3}{2}|+3}

Step-by-step explanation:

The translation is a horizontal translation.

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Sandra's salary the previous year was $41,000

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Please check the files attached for more explanation

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