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podryga [215]
3 years ago
12

The kinetic energy of a 44 kg-cheetah running at 31 m/s is

Physics
1 answer:
iren2701 [21]3 years ago
7 0
The answer is 21142 Joules hope this helped cause im sorry if this didnt
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A force of 73.8 newtons is applied to travel bag at an angle 39.0° with the horizontal. What are the horizontal and vertical com
Semenov [28]
The horizontal component of the force is the product of the cosine of the angle and the magnitude of the force, Fx = (73.8 N)(cos 39) = 57.35 N. The vertical component of this force is the product of the sine of the angle and the force, Fy = (73.8 N)(sin 39) = 46.44 N.
5 0
3 years ago
Resultant Displacement. I WILL GIVE BRAINLIEST!!!!
aleksley [76]

Answer:

displacement will be 83km from the marker that reads 249km.

8 0
3 years ago
Hi :) I don’t really understand why it’s A
Troyanec [42]

Answer:

A

Explanation:

1. When the block moves across a table top, F(pulling) = - F(frictional).

Sum of this forces = 0, so the block moves with uniform speed.

2. When the block is pulled on top of the table covered with beads

F(pulling) > - F(frictional).

So, the sum of forces (∑F) is a number that is more than 0 and directed to the direction of movement.

So,  a = ∑F / m is positive and constant. Speed is increasing because

v(t) = v(0)+at

a is constant and  directed forward.

That means a is acceleration, and constant.

6 0
4 years ago
Find the velocity (in m/s) of a proton that has a momentum of 4.96 X 10^-19 kg.m/s.
kramer

Answer:

The velocity of the proton is 2.965*10^{8} \frac{m}{s}

Explanation:

The momentum of a particle is defined as the product of its mass by its velocity and we can calculate it using the following formula:

p=m*v Equation (1)

Where:

p: Is the momentum in kg*m/s

m: Is mass of the particle in kg

v: Is the velocity of the particle in m/s

Data known:

m= 1,6726 × 10^–27 kg : mass of the proton

p= 4.96 X 10^-19 kg.m/s.

We replace this data in the Equation (1):

4,96*10^{-19} =1.6726*10^{-27} *vv=\frac{4.9*10^{-19} }{1.6726*10^{-27} }

v=(\frac{4.96}{1.6726} )*(10^{27-19} )

v=2,965*10^{8} m/s

Answer: The velocity of the proton is 2.965*10^{8} \frac{m}{s}

3 0
3 years ago
2. A digital camera records each image as 8 megapixels, with each pixel transferring 14 bits of information. What is the minimum
Sholpan [36]

Given what we know, we can confirm that due to its relatively low image quality, any memory card with at least one MB will be sufficient to hold the 120 images taken.

<h3>Why is one MB enough?</h3>

The photos are taken at 8 megapixels, with each one occupying 14 bits of information. A megabit consists of one million bits of potential storage. Therefore, the 120 pictures will occupy roughly 1% of the available storage of a 1 MB memory card.


Therefore, we can confirm that due to its relatively low image quality, any memory card with at least one MB will be sufficient to hold the 120 images taken.

To learn more about megabits visit:

brainly.com/question/22735284?referrer=searchResults

7 0
3 years ago
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