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3 years ago

7

Object A with more mass, and object B with less mass. If you want to make both objects accelerate at the same rate, which of the

two objects will require a greater force? Why?

2 answers:

kondaur [170]3 years ago

8 0

Answer: object a

Explanation:

tia_tia [17]3 years ago

5 0

Answer:

Object a

Explanation:

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You slide a chair across a rough, horizontal surface. The chair's mass is 18.8 kg. The force you exert on the chair is 156 N dir

Luda [366]

Answer:

626.612 J

Explanation:

Work done by friction on the chair is given as

W-ΔEk = W'..................... Equation 1

Where W' = Work done by friction on the chair, W = Work done on the chair by me, Ek = change in Kinetic energy of the chair as a result of the slide.

From the question,

W = FdcosФ.............. Equation 2

ΔEk = 1/2m(v²-u²)................ Equation 3

Where F = Force applied on the chair, d = distance of slide, Ф = angle between the force and the horizontal, m = mass of the chair, v = final velocity of the chair, u = initial velocity of the chair

Substitute equation 2 and equation 3 into equation 1

W' = FdcosФ-1/2m(v²-u²)........................ Equation 4

Given: F = 156, d = 5 m, Ф = 26°, m = 18.8 kg, v = 3.1 m/s, u = 1.3 m/s

Substitute into equation 4

W' = 156×5×cos26°-1/2×18(3.1²-1.3²)

W' = 701.06-74.448

W' = 626.612 J.

Hence the work done by friction = 626.612 J

8 0

3 years ago

Mechanical advantage what does this mean for a simple machine

lyudmila [28]

Mechanical advantage is a measure of the force amplification achieved by using a tool, mechanical device or machine system. Ideally, the device preserves the input power and simply trades off forces against movement to obtain a desired amplification in the output force. The model for this is the <span>law of the lever.</span> Machine components designed to manage forces and movement in this way are called mechanisms. An ideal mechanism transmits power without adding to or subtracting from it. This means the ideal mechanism does not include a power source, and is frictionless and constructed from rigid bodies that do not deflect or wear. The performance of a real system relative to this ideal is expressed in terms of efficiency factors that take into account friction, deformation and wear.

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3 years ago

A rock is thrown at an angle of 60∘ to the ground. If the rock lands 25m away, what was the initial speed of the rock? (Assume a

Zinaida [17]

Answer:

$v_0 = 16.82\ m/s$

Explanation:

given,

angle at which rock is thrown = 60°

rock lands at distance,d = 25 m

initial speed of rock, = ?

In horizontal direction

distance = speed x time

d = v₀ cos 60° t

25 = v₀ cos 60° t............(1)

now,

in vertical direction

displacement in vertical direction is zero

using equation of motion

$s = ut +\dfrac{1}{2}gt^2$

$0 =v_0 sin 60^0 t - 4.9 t^2$

$v_o sin 60^0 = 4.9 t$

$t = \dfrac{v_0 sin 60^0}{4.9}$

putting the value of t in equation (1)

$25 = v_0 cos 60^0\times \dfrac{v_0 sin 60^0}{4.9}$

$25 =\dfrac{v_0^2cos 60^0 sin 60^0}{4.9}$ v

$v_0^2 = 282.90$

$v_0 = 16.82\ m/s$

Hence, the initial speed of the rock is equal to 16.82 m/s

4 0

3 years ago

Which of the following is an example of heat being transferred by radiation? Choose all that apply, Fire, Sun, Candle Flame, Sto

OlgaM077 [116]

Answer:

Fire, Sun, Candle Flame, Stove

4 0

3 years ago

Read 2 more answers

A 4500 kg car accelerates from rest to 45.0

Llana [10]

The car undergoes an acceleration <em>a</em> such that

(45.0 km/h)² - 0² = 2 <em>a</em> (90 m)

90 m = 0.09 km, so

(45.0 km/h)² - 0² = 2 <em>a</em> (0.09 km)

Solve for <em>a</em> :

<em>a</em> = (45.0 km/h)² / (2 (0.09 km)) = 11,250 km/h²

Ignoring friction, the net force acting on the car points in the direction of its movement (it's also pulled down by gravity, but the ground pushes back up). Newton's second law then says that the net force <em>F</em> is equal to the mass <em>m</em> times the acceleration <em>a</em>, so that

<em>F</em> = (4500 kg) (11,250 km/h²)

Recall that Newtons (N) are measured as

1 N = 1 kg • m/s²

so we should convert everything accordingly:

11,250 km/h² = (11,250 km/h²) (1000 m/km) (1/3600 h/s)² ≈ 0.868 m/s²

Then the force is

<em>F</em> = (4500 kg) (0.868 m/s²) = 3906.25 N ≈ 3900 N

8 0

4 years ago