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goblinko [34]
3 years ago
6

In right triangle ABC, angle C is a right angle and sin A= sin B. What is measure of angle A

Mathematics
1 answer:
natulia [17]3 years ago
3 0

Answer:

I NEED THE ANGLES PLEASEEEE

Step-by-step explanation:

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x=67.5

Step-by-step explanation:

A full circle is 360°, and the right angle is 90°. The rest of the angle is 270°, or 4x (from 3x+x).

4x = 270

<u>x=67.5</u>

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6. What is 45% of 900?
Crazy boy [7]

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405

Step-by-step explanation:

45% of 900

=(45/100) . 900

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How does the graph of g(x)=1/x+4 -6
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7 0
3 years ago
A particle moves along line segments from the origin to the points (2, 0, 0), (2, 4, 1), (0, 4, 1), and back to the origin under
Shkiper50 [21]

The work is equal to the line integral of \vec F over each line segment.

Parameterize the paths

  • from (0, 0, 0) to (2, 0, 0) by \vec r_1(t)=t\,\vec\imath with 0\le t\le2,
  • from (2, 0, 0) to (2, 4, 1) by \vec r_2(t)=2\,\vec\imath+4t\,\vec\jmath+t\,\vec k with 0\le t\le1,
  • from (2, 4, 1) to (0, 4, 1) by \vec r_3(t)=(2-t)\,\vec\imath+4\,\vec\jmath+\vec k with 0\le t\le2, and
  • from (0, 4, 1) to (0, 0, 0) by \vec r_4(t)=(4-4t)\,\vec\jmath+(1-t)\,\vec k with 0\le t\le1

The work done by \vec F over each segment (call them C_1,\ldots,C_4) is

\displaystyle\int_{C_1}\vec F\cdot\mathrm d\vec r_1=\int_0^2\vec0\cdot\vec\imath\,\mathrm dt=0

\displaystyle\int_{C_2}\vec F\cdot\mathrm d\vec r_2=\int_0^1(t^2\,\vec\imath+24t\,\vec\jmath+32t^2\,\vec k)\cdot(4\,\vec\jmath+\vec k)\,\mathrm dt=\int_0^1(96t+32t^2)\,\mathrm dt=\frac{176}3

\displaystyle\int_{C_3}\vec F\cdot\mathrm d\vec r_3=\int_0^2(\vec\imath+(24-12t)\,\vec\jmath+32\,\vec k)\cdot(-\vec\imath)\,\mathrm dr=-\int_0^2\mathrm dt=-2

\displaystyle\int_{C_4}\vec F\cdot\mathrm d\vec r_4=\int_0^1((1-t)^2\,\vec\imath+2(4-4t)^2\,\vec k)\cdot(-4\,\vec\jmath-\vec k)\,\mathrm dt=-2\int_0^1(4-4t)^2\,\mathrm dt=-\frac{32}3

Then the total work done by \vec F over the particle's path is 46.

8 0
4 years ago
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