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Natasha2012 [34]
3 years ago
6

How do the perimeters of the triangles compare? Original: height-18, slant-30, length-24 Scaled: height-6, slant-10, length-8 A)

the scaled triangles perimeter is 3x's larger than the original triangles perimeter. B) the scaled triangles perimeter is 6x's smaller than the original triangles perimeter C) the scaled triangles perimeter is 1/9 the size of the original triangles perimeter D) the scaled triangles perimeter is 1/3 the size of the original triangles perimeter
Mathematics
1 answer:
SVEN [57.7K]3 years ago
7 0

Answer:

D) the scaled triangles perimeter is 1/3 the size of the original triangles perimeter

Step-by-step explanation:

Given

Original:

Height = 18, Slant = 30, Length =24

Scaled:

Height =6, Slant=10, Length=8

Looking at the dimension of both triangles, The relationship between the original and the scaled copy is:

Scaled = \frac{1}{3} * Original

Hence, the perimeter is:

Perimeter (Scaled) = \frac{1}{3} * Perimeter (Original)

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What is the area of this figure? I give brainliest and thanks :)
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591 square cm

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Step-by-step explanation:

Data Set A: 14, 21, 24, 28, 28, 35

Data Set B: 18, 19, 21, 25, 29,32

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A veterinarian weighed a sample of 666 puppies. Here are each of their weights (in kilograms): 1, 2, 7, 7, 10, 151,2,7,7,10,151,
rjkz [21]

Answer:

The standard deviation of the weight, σ, is approximately 4.73 kg

Step-by-step explanation:

The weights of the six puppies are;

x_i = 1, 2, 7, 7, 10, and 15

The number of puppies, n = 6

Therefore, we have;

The mean = μ = ∑x/n = (1 + 2 + 7 + 7 + 10 + 15)/6 = 7

The standard deviation, σ, is given as follows;

\sigma =\sqrt{\dfrac{\sum \left (x_i-\mu  \right )^{2} }{n}}

By substituting, we have;

\sigma =\sqrt{\dfrac{ \left (1-7  \right )^{2} + \left (2-7  \right )^{2} + \left (7-7  \right )^{2} + \left (7-7  \right )^{2} + \left (10-7  \right )^{2} + \left (15-7  \right )^{2} }{6}}

Simplifying gives;

\sigma =\sqrt{\dfrac{ \left (-6  \right )^{2} + \left (-5  \right )^{2} + \left (0  \right )^{2} + \left (0  \right )^{2} + \left (3 \right )^{2} + \left (8  \right )^{2} }{6}} =\sqrt{\dfrac{ 36 + 25 + 0 +0+ 9 + 64 }{6}}

\sigma =\sqrt{\dfrac{ 134 }{6}} = \sqrt{\dfrac{67}{3} } \approx 4.72582

The standard deviation of the weight, σ ≈ 4.73 kg to two decimal places.

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= 84° 15'

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3 years ago
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