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Tomtit [17]
3 years ago
9

Write the standard equation for the circle that passes through the points: (-1, 2) (4, 2) (- 3, 4)

Mathematics
1 answer:
vazorg [7]3 years ago
5 0

Answer:

(

x

−

5

3

)

2

+

(

y

−

5

3

)

2

−

65

9

=

0

Explanation:

The circle's general equation is

C

→

(

x

−

x

0

)

2

+

(

y

−

y

0

)

2

−

r

2

=

0

This equation must be obeyed by the three points. Substituting  

{

x

,

y

}

for each point we have

⎧

⎪

⎪

⎨

⎪

⎪

⎩

2

x

0

+

x

2

0

−

4

y

0

+

y

2

0

+

5

−

r

2

=

0

−

6

x

0

+

x

2

0

−

8

y

0

+

y

2

0

+

25

−

r

2

=

0

−

4

x

0

+

x

2

0

+

2

y

0

+

y

2

0

+

5

−

r

2

=

0

Those equations are easily handled taking the difference between the first and the second, and the first and the third, obtaining

{

2

x

0

+

y

0

−

5

=

0

x

0

−

y

0

=

0

Solving for  

x

0

,

y

0

we obtain

{

x

0

=

5

3

,

y

0

=

5

3

}

r

is obtained putting those results in any of the equations already obtained

r

=

√

65

3

Step-by-step explanation:

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Vlada [557]

We need to simplify the expression:

12x^{-6}y^{10} \times (3x^{7}y)

Now, we know that we can resolve the exponents of the variables with the like terms only and we can multiply the coefficients independently:

Now,  

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3 years ago
The U.S.A. Olympic Synchronized Swimming Team is designing a routine for their upcoming competition. From the center of the pool
Mama L [17]

Answer:

The equation of the circle is;

(x - 2)² + (y - 4)² = 5²  

Step-by-step explanation:

We note that the general equation of a circle is given as follows;

(x - h)² + (y - k)² = r²

Where;

(h, k) = The coordinates of the center of the circle

r = The radius of the circle

The given parameters are;

The location of the center of the pool to the center of their formation = 2 feet to the right and 4 feet up from the center of the pool

The point through which the circle which they form goes through = A point 3 feet to the left and 4 feet up from the center of their formation

Taking the center of the pool as the origin of the coordinate plane system, we have;

The coordinate of the center of the circle = The coordinate of their motion from the center of the circle

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∴ (h, k) = (2, 4)

h = 2, k = 4

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r = 5

The equation of the circle is therefore presented by substituting the values of 'h', 'k', and 'r', as follows;

(x - 2)² + (y - 4)² = 5².

4 0
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