Answer:
<u>The probability that a randomly selected boy in school can run the mile in less than 348 seconds is 1.1%.</u>
Step-by-step explanation:
1. Let's review the information provided to us to answer the question correctly:
μ of the time a group of boys run the mile in its secondary- school fitness test = 440 seconds
σ of the time a group of boys run the mile in its secondary- school fitness test = 40 seconds
2. Find the probability that a randomly selected boy in school can run the mile in less than 348 seconds.
Let's find out the z-score, this way:
z-score = (348 - 440)/40
z-score = -92/40 = -2.3
Now let's find out the probability of z-score = -2.3, using the table:
p (-2.3) = 0.0107
p (-2.3) = 0.0107 * 100
p (-2.3) = 1.1% (rounding to the next tenth)
<u>The probability that a randomly selected boy in school can run the mile in less than 348 seconds is 1.1%.</u>
Answer:
Step-by-step explanation:
1.
-4, -2, 0, 4, 10
2.
-2.9, -2.83, -2.09, 2.07, 2.56
3.
-3, -1/10, 1/10, 1/2, 7/8
4.
-3, -2, -0.8, -1/10, 1/2, 0.8, 7
this image might help :))
Answer:
32 remaining cups for Kin
Step-by-step explanation:
Answer:
rate=55 percent
Step-by-step explanation:
SI=PRT
p=90
r=?
t=2
si=99
R=SI÷PT
R=99÷90×2
r=99÷180=0.55
r=0.55×100
R=55%
