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cestrela7 [59]
2 years ago
15

Simplify the expression. 12x^-6 y^10 times 3x^7 y

Mathematics
1 answer:
Vlada [557]2 years ago
7 0

We need to simplify the expression:

12x^{-6}y^{10} \times (3x^{7}y)

Now, we know that we can resolve the exponents of the variables with the like terms only and we can multiply the coefficients independently:

Now,  

12x^{-6}y^{10} \times 3x^{7}y=(12 \times 3)\times (x^{-6}\times x^{7})\times (y^{10}\times y)

On simplifying the above expression we get:

36\times x^{(-6+7)}\times y^{(10+1)}

=36 \times x^{1}\times y^{11}

=36 \times x \times y^{11}

=36xy^{11}

So the simplified form of the expression 12x^{-6}y^{10} \times 3x^{7}y=36xy^{11}.

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The speeds of vehicles traveling on a highway are normally distributed with an unkown population mean and standard deviation. A
Maksim231197 [3]

Answer:

The 90% confidence interval would be given by (60.09;69.91)    

We are 90% confident that the true mean for the speeds of vehicles traveling on a highway is between 60.09 and 69.91 miles per hour.

Step-by-step explanation:

1) Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X =65 represent the sample mean for the sample  

\mu population mean (variable of interest)

s=9 represent the sample standard deviation

n=11 represent the sample size  

2) Confidence interval

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

In order to calculate the critical value t_{\alpha/2} we need to find first the degrees of freedom, given by:

df=n-1=11-1=10

Since the Confidence is 0.90 or 90%, the value of \alpha=0.1 and \alpha/2 =0.05, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.05,10)".And we see that t_{\alpha/2}=1.81

Now we have everything in order to replace into formula (1):

65-1.81\frac{9}{\sqrt{11}}=60.09    

65+1.81\frac{9}{\sqrt{11}}=69.91

So on this case the 90% confidence interval would be given by (60.09;69.91)    

We are 90% confident that the true mean for the speeds of vehicles traveling on a highway is between 60.09 and 69.91 miles per hour.

3 0
3 years ago
as a contractor to make a hole 4 5/8 inches diameter. express the mixed number as an improper fraction.
san4es73 [151]

The mixed number as an improper fraction is 37/8

<h3>How to express the mixed number as an improper fraction?</h3>

The diameter is give as:

Diameter = 4 5/8

Next we convert the above number to an improper fraction

The numerator is calculated as

Numerator = 8 * 4 + 5

This gives

Numerator = 37

Hence, the mixed number as an improper fraction is 37/8

Read more about fractions at:

brainly.com/question/18734292

#SPJ1

7 0
1 year ago
16) w(x) = 4x + 4; Find w(x + 4)
Zina [86]

\\ \tt\hookrightarrow w(x)=4x+4=4(x+1)

Now

\\ \tt\hookrightarrow w(x+4)=4(x+4+1)

\\ \tt\hookrightarrow w(x+4)=4(x+5)

\\ \tt\hookrightarrow w(x+4)=4x+20

3 0
2 years ago
Which statements are true for the given quadrilaterals?
notka56 [123]
A rectangle is considered a special case of a parallelogram because: Aparallelogram is a quadrilateral with 2 pairs of opposite, equal and parallel sides. Arectangle is a quadrilateral with 2 pairs of opposite, equal and parallel sides BUT ALSO forms right angles between adjacent sides.
6 0
3 years ago
Which additional information could be used to prove that the triangles are congruent using AAS or ASA? Check all that apply.
Ad libitum [116K]

Consider the given triangles.

Given: \angle C \cong \angle Q

ASA congruence criterion states that if two angles and the included side of one triangle are congruent to the corresponding parts of another triangle, then the triangles are congruent.

AAS congruence criterion states that if two angles and a non-included side of one triangle are congruent to the corresponding parts of another triangle, then the triangles are congruent.

Consider the first part:

1. In triangles ABC and QPT

If we take \angle B \cong \angle P , BC \cong PQ along with the given condition.

Then the triangles are congruent by ASA congruence criterion.

2. If we take \angle A \cong \angle T and AC= TQ=3.2 along with the given condition.

Then the triangles are congruent by ASA congruence criterion.

3. As,\angle C \cong \angle Q, \angle A \cong \angle T and \angle B \cong \angle P, so the triangles can not be congruent.

4. If we take \angle A \cong \angle T and BC \cong PQ along with the given condition.

Then the triangles are congruent by AAS congruence criterion.

5. If we take AC=TQ=3.2 and CB=QP=3.2 along with the given condition, then the triangles are congruent but by SAS congruence criteria neither by ASA nor AAS congruence criterion.

7 0
3 years ago
Read 2 more answers
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