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cestrela7 [59]
3 years ago
15

Simplify the expression. 12x^-6 y^10 times 3x^7 y

Mathematics
1 answer:
Vlada [557]3 years ago
7 0

We need to simplify the expression:

12x^{-6}y^{10} \times (3x^{7}y)

Now, we know that we can resolve the exponents of the variables with the like terms only and we can multiply the coefficients independently:

Now,  

12x^{-6}y^{10} \times 3x^{7}y=(12 \times 3)\times (x^{-6}\times x^{7})\times (y^{10}\times y)

On simplifying the above expression we get:

36\times x^{(-6+7)}\times y^{(10+1)}

=36 \times x^{1}\times y^{11}

=36 \times x \times y^{11}

=36xy^{11}

So the simplified form of the expression 12x^{-6}y^{10} \times 3x^{7}y=36xy^{11}.

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Which multiplication equation represents the question: how many 3/8s are in 5/4?
Harman [31]

Answer:

The equation which represents the question is 3 1/3

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Which inequality matches the given situation if w represents weight in pounds:Baby tigers can be no larger than 4 pounds.
ozzi

Given:

w be the weight in pounds of a baby tigers.

To find:

The inequality if baby tigers can be no larger than 4 pounds.

Solution:

Baby tigers can be no larger than 4 pounds. It mean weight of baby tigers cannot be greater than 4. In other words, the weight of the baby tigers must be less than or equal to 4.

Let w represents weight in pounds and the weight of the baby tigers must be less than or equal to 4. So,

w\leq 4

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4 0
3 years ago
Answer it pls option c
Troyanec [42]

Answer:

x = \frac{1}{4}

Step-by-step explanation:

\frac{x}{2} +\frac{3}{4} =\frac{7}{8}

→ Find the LCM of the denominators (2,4 and 8)

LCM = 8

→ Multiply the whole equation by 8 to get rid of the fractions

4x + 6 = 7

→ Minus 6 from both sides to isolate 4x

4x = 1

→ Divide both sides by 4 to isolate x

x = \frac{1}{4}

5 0
3 years ago
Read 2 more answers
Find the area of the circle. Round your answer to the nearest tenth. The circle has a radius of 9
Rudik [331]

Answer:

I is at least ten because of nine it rounds to ten

3 0
3 years ago
NEEEEEEDDDDD HELP ASAP
mash [69]
The correct answer is that there is more variability in the heights of the volleyball team members.

The mean absolute deviation shows us how spread out the data is, so the larger the mean absolute deviation the higher the variability.

Both teams have players that are 76 inches tall, so the last two statements cannot be true.
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