Answer:
1.120 degree
2.100 degree
3.180 degree
4.300 degree
5.240 degree
6.240 degree
7.240 degree
Step-by-step explanation:
1.
If -3 + i is a root of the polynomial function f(x), -3 - i must also be a root of f(x)
<h3>How to determine the true statement?</h3>
The root of the polynomial function is given as:
-3 + i
The above root is a complex root.
If a polynomial has a complex root, then the conjugate of the root is also a root of the function
The conjugate of -3 + i is -3 - i
Hence, if -3 + i is a root of the polynomial function f(x), -3 - i must also be a root of f(x)
Read more about polynomial functions at:
brainly.com/question/20896994
None of them are right triangles.
Hope This Helps!!!
Answer:
So after the second tablet there is 360-mg of drug in the body.
So after the third tablet there is 372-mg of drug in the body.
Step-by-step explanation:
We know that a doctor prescribes a 300-mg antibiotic tablet to be taken every eight hours. Just before each tablet is taken, 20% of the drug remains in the body.
We know that 20%=0.2.
We conclude that after the first pill, 300mg of the drug is in the body.
We have the following formula, to calculate how much mg of the drug is in the body after the second tablet:

So after the second tablet there is 360-mg of drug in the body.
We have the following formula, to calculate how much mg of the drug is in the body after the third tablet:

So after the third tablet there is 372-mg of drug in the body.
Answer:
the time taken for the radioactive element to decay to 1 g is 304.8 s.
Step-by-step explanation:
Given;
half-life of the given Dubnium = 34 s
initial mass of the given Dubnium, m₀ = 500 grams
final mass of the element, mf = 1 g
The time taken for the radioactive element to decay to its final mass is calculated as follows;
![1 = 500 (0.5)^{\frac{t}{34}} \\\\\frac{1}{500} = (0.5)^{\frac{t}{34}}\\\\log(\frac{1}{500}) = log [(0.5)^{\frac{t}{34}}]\\\\log(\frac{1}{500}) = \frac{t}{34} log(0.5)\\\\-2.699 = \frac{t}{34} (-0.301)\\\\t = \frac{2.699 \times 34}{0.301} \\\\t = 304.8 \ s](https://tex.z-dn.net/?f=1%20%3D%20500%20%280.5%29%5E%7B%5Cfrac%7Bt%7D%7B34%7D%7D%20%5C%5C%5C%5C%5Cfrac%7B1%7D%7B500%7D%20%3D%20%20%280.5%29%5E%7B%5Cfrac%7Bt%7D%7B34%7D%7D%5C%5C%5C%5Clog%28%5Cfrac%7B1%7D%7B500%7D%29%20%3D%20log%20%5B%280.5%29%5E%7B%5Cfrac%7Bt%7D%7B34%7D%7D%5D%5C%5C%5C%5Clog%28%5Cfrac%7B1%7D%7B500%7D%29%20%20%3D%20%5Cfrac%7Bt%7D%7B34%7D%20log%280.5%29%5C%5C%5C%5C-2.699%20%3D%20%5Cfrac%7Bt%7D%7B34%7D%20%28-0.301%29%5C%5C%5C%5Ct%20%3D%20%5Cfrac%7B2.699%20%5Ctimes%2034%7D%7B0.301%7D%20%5C%5C%5C%5Ct%20%3D%20304.8%20%5C%20s)
Therefore, the time taken for the radioactive element to decay to 1 g is 304.8 s.