What is 78/126 in simplest form

Find the least common denominator for these two rational expressions

coldgirl [10]

Answer: The LCD is 5y.

I hope this helps!

4 0

2 years ago

Assume that the paired data came from a population that is normally distributed. using a 0.05 significance level and dequalsxmin

Artemon [7]

"Assume that the paired data came from a population that is normally distributed. Using a 0.05 significance level and d = (x - y), find $\bar{d}$ , $s_{d}$ , the t-test statistic, and the critical values to test the claim that $\mu_{d} = 0$ "

You did not attach the data, therefore I can give you the general explanation on how to find the values required and an example of a random paired data.

For the example, please refer to the attached picture.

A) Find $\bar{d}$
You are asked to find the mean difference between the two variables, which is given by the formula:
$\bar{d} = \frac{\sum (x - y)}{n}$

These are the steps to follow:
1) compute for each pair the difference d = (x - y)
2) sum all the differences
3) divide the sum by the number of pairs (n)

In our example:
 $\bar{d} = \frac{6}{8} = 0.75$ 

B) Find $s_{d}$
You are asked to find the standard deviation, which is given by the formula:
 $s_{d} = \sqrt{ \frac{\sum(d - \bar{d}) }{n-1} }$

These are the steps to follow:
1) Subtract the mean difference from each pair's difference
2) square the differences found
3) sum the squares
4) divide by the degree of freedom DF = n - 1

In our example:
$s_{d} = \sqrt{ \frac{101.5}{8-1} }$
= √14.5
= 3.81

C) Find the t-test statistic.
You are asked to calculate the t-value for your statistics, which is given by the formula:
$t = \frac{(\bar{x} - \bar{y}) - \mu_{d} }{SE}$

where SE = standard error is given by the formula:
$SE = \frac{ s_{d} }{ \sqrt{n} }$

These are the steps to follow:
1) calculate the standard error (divide the standard deviation by the number of pairs)
2) calculate the mean value of x (sum all the values of x and then divide by the number of pairs)
3) calculate the mean value of y (sum all the values of y and then divide by the number of pairs)
4) subtract the mean y value from the mean x value
5) from this difference, subtract $\mu_{d}$
6) divide by the standard error

In our example:
SE = 3.81 / √8
= 1.346

The problem gives us $\mu_{d} = 0$ , therefore:
t = [(9.75 - 9) - 0] / 1.346
= 0.56

D) Find $t_{\alpha / 2}$
You are asked to find what is the t-value for a 0.05 significance level.

In order to do so, you need to look at a t-table distribution for DF = 7 and A = 0.05 (see second picture attached).

We find $t_{\alpha / 2} = 1.895$ 

Since our t-value is less than $t_{\alpha / 2}$ we can reject our null hypothesis!!

7 0

3 years ago

A garden is made up of two squares and a quarter circle. What is the area of the garden?

Elanso [62]

9514 1404 393

Answer:

100.27 ft^2

Step-by-step explanation:

The area of each square is ...

A = s^2 = (6 ft)^2 = 36 ft^2

The area of the 1/4 circle is ...

A = 1/4πr^2 = 1/4π(6 ft)^2 = 9π ft^2 ≈ 28.27 ft^2

__

The area of the garden is the sum of the areas of the quarter circle and the two squares:

A = 28.27 ft^2 + 2×36 ft^2 = 100.27 ft^2

The area of the garden is about 100.27 square feet.

7 0

2 years ago

what is the next logical statement in the proof below? given M is the midpoint of AB what reason justifies the reason the the pr

Pavel [41]

Answer -
AB = AM + MB

6 0

3 years ago

2^5*2^3/4^4 plz answer

Alexxx [7]

Answer:

1

Step-by-step explanation:

Because they both of the same base, we can merge 2^5 and 2^3 into one term: 2^8 (2^(3+5))

4 is = 2^2 so we can change 4^4 to 2^8.

(2^(2*4)).

Thia means we now have 2^8/2^8 which is 1.

As anything divided by itself is just 1.

Hope this helped!

8 0

3 years ago