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Marta_Voda [28]
3 years ago
11

What is the gcf of 30 and 54

Mathematics
2 answers:
iren [92.7K]3 years ago
8 0
The greatest common factor is the biggest whole number that can go into both of them so

first find the factors and collect the ones common to both of them

30=2 times 3 times 5
54=2 times 3 times 3 times 3

the ones common to them both is 2 times 3 which is 6
ANEK [815]3 years ago
7 0
30|2
15|3
5|5
1

54|2
27|3
9|3
3|3
1

GCF(30,54)=2\cdot3=6
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Suppose a 50-foot ladder is leaning against a wall. Which statements about the base of the ladder are true?
Liula [17]

Answer and Step-by-step explanation:

These are the statements that make the question complete:

A. If the base is 24 feet from the wall, the ladder reaches 45 feet up the wall.

B. If the base is 30 feet from the wall, the ladder reaches 40 feet up the wall.

C. If the base is 27 feet from the wall, the ladder reaches 44 feet up the wall.

D. If the base is 14 feet from the wall, the ladder reaches 48 feet up the wall.

Since the ladder leans against a wall, a right angle triangle is formed. Since the ladder is now slant, then it's length becomes the hypothenuse.

The correct statements can be gotten through Pythagoras theorem which says:

A² + B² = C² where C is the hypothenuse and A and B are the other two sides.

Since the hypothenuse is 50, we can test each statement by taking the square of the two sides and add them up, if they are equal to 50² = 2500, then the statement is true.

A. 24² + 45² = 576 + 2025 = 2601 ≠ 2500, therefore it is false.

B. 30² + 40² = 900 + 1600 = 2500, therefore it is true.

C. 27² + 44² = 729 + 1936 = 2665 ≠ 2500, therefore it is false

D. 14² + 48² = 196 + 2304 = 2500, therefore it is true.

From here, statements B and D are true while the rest are all false.

7 0
3 years ago
A spinner is divided into 8 section of equal size. The sections are numbered 1 through 8. Use this information to determine the
olga_2 [115]

1) 1/8

2) 1/2

Step-by-step explanation:

1)

First of all, we notice that the spinner is divided into 8 sections of equal size.

So the number of sections is

n = 8

Secondly, we note that each section has the same size: this means that the probability of the spinner landing on each section is the same.

The probabilty of a certain event A to occur is given by

p(A)=\frac{a}{n}

where

a is the number of successfull outcomes (in which A occurs)

n is the total number of possible outcomes

Here we want to find

p(7) = probability that the spinner lands on section 7

Here we have:

a=1 (only 1 outcome is successfull: the one in which the spinner lands on section 7)

n=8

Therefore, the probability is

p(7)=\frac{1}{8}

2)

Here we want to find the probability that the spinner lands on an even numbered section.

As before, the total number of possible outcomes his:

n=8

which corresponds to: 1, 2, 3, 4, 5, 6, 7, 8

The even-numbered sections are:

2, 4, 6, 8

So, the number of successfull outcomes is

a=4

Because there are only 4 even-numbered sections.

Therefore, the probability that the spinner lands on an even numbered section is:

p(e)=\frac{a}{n}=\frac{4}{8}=\frac{1}{2}

8 0
2 years ago
3 packs of soda cost $10 less than 5 packs of soda. Write and equation that models this, and solve.
zysi [14]
<span>Cost 1 pack = x
3x + 10 = 5x
2x = 10
x = 5
1 pack cost $5
Hope this helped</span>
8 0
3 years ago
A triangle with vertices at A(0, 0), B(0, 4), and C(6, 0) is dilated to yield a triangle with vertices at A′(0, 0), B′(0, 10), a
Vesnalui [34]

Answer:

2.5

Step-by-step explanation:

A triangle ABC with vertices A(0, 0), B(0, 4), and C(6, 0) is dilated to form a triangle A'B'C' with vertices A′(0, 0), B′(0, 10), and C′(15, 0). If the center of dilation is point A or A' (the origin), then

\dfrac{A'B'}{AB}=\dfrac{A'C'}{AC}.

Since

  • AB=4;
  • A'B'=10;
  • AC=6;
  • A'C'=15,

then the scale factor of the dilation is

k=\dfrac{10}{4}=\dfrac{15}{6}=2.5.

3 0
3 years ago
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Andrews [41]
So you need to find the $ for one hour of work
if 16=135
1 hour= $8.50
$8.50*24= $204
answer=$204
hope this helps :)
3 0
3 years ago
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