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2 years ago

6 sin 2 ⁡ x + 4 cos 2 ⁡ x ≡ A + B cos 2 ⁡ x where A and B are integers. Work out the values of A and B .

1 answer:

7 0

$\textit{Pythagorean Identities} \\\\ sin^2(\theta)+cos^2(\theta)=1\implies sin^2(\theta)=1-cos^2(\theta) \\\\[-0.35em] ~\dotfill\\\\ 6sin^2(x)+4cos^2(x)\implies 6[~1-cos^2(x)~]+4cos^2(x) \\\\\\ 6-6cos^2(x)+4cos^2(x)\implies \stackrel{A}{6}~~ \stackrel{B}{-2}cos^2(x)$

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What is the value of |−8.6| a −8.6 b −1.4 c 1.4 d 8.6 thanks

nikklg [1K]

Hi!

When a number has lines on the outside of it like that, it means that it's the distance from 0. It's known as the absolute value.

|−8.6|'s distance from 0 is 8.6.

The answer is d 8.6

Hope this helps! :)

-Peredhel

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3 years ago

Are the lengths of the side of the square and perimeter of the square related proportionally? Why or why not

telo118 [61]

Answer:

They are proportional

Step-by-step explanation:

becaue the length of one of the square's sides is 1/4 the perimeter

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3 years ago

The graph of a transformed parabola (green) is

tino4ka555 [31]

The vertex is (-4,5)

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3 years ago

Your first assignment at El Smello Perfume Co. is to determine the proper setting for filling the bottles. The company wishes to

SCORPION-xisa [38]

Answer:

The answer is "96.864 ml".

Step-by-step explanation:

In this question, the formula of $\bold{CI = X \pm t \times s}$ .

( where X is the mean, t is the coefficient, and s is the mean difference error)

As a result, only 2.5% of containers might include less than 100 ml of volume, its trust coefficient could indeed be used in accordance with 95%, which is $t=1.96$ .

And it can take $\pm \ 1.6 \ ml$ to have been the full value the standard infinite: $\to CI = 100 \pm (1.96 \times 1.6) \\\\$

$= 100 \pm (3.136) \\\\$

Consequently, if the standard error is $\pm \ 1.6 \ ml$ , a similar amount should be used to fill

$= 100 - 3.136 \\\\= 96.864 \ \ mL$

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3 years ago

3.The following are real data from Santa Clara County, CA. As of a

zepelin [54]

I) the probability that the person is female is 8.33%.
II) the probability that the person has a risk factor heterosexual contact is 6.40%.
III) the probability that the person is female or has a risk factor of IV drug user is 23.47%.
IV) the probability that the person is female and has a risk factor of homosexual is 0%.
V) the probability that the person is male and has a risk factor of IV drug user is 15.13%.
VI) the probability that the person is female given that the person got the disease from heterosexual contact is 69.38%.

Given the data mentioned in the table, the following calculations must be performed to obtain the requested probabilities:

I.-

(0 + 70 + 136 + 49) / (2,146 + 463 + 60 + 135 + 0 + 70 + 136 + 49) = X

255/3059 = X

0.0833 = X

II.-

196/3059 = X

0.0640 = X

III.-

(255 + 463) / 3059 = X

718/3059 = X

0.2347 = X

IV.-

0/3059 = X

0 = X

V.-

463/3059 = X

0.1513 = X

VI.-

136/196 = X

0.6938 = X

Therefore, I) the probability that the person is female is 8.33%, II) the probability that the person has a risk factor heterosexual contact is 6.40%, III) the probability that the person is female or has a risk factor of IV drug user is 23.47%, IV) the probability that the person is female and has a risk factor of homosexual is 0%, V) the probability that the person is male and has a risk factor of IV drug user is 15.13%, and VI) the probability that the person is female given that the person got the disease from heterosexual contact is 69.38%.

Learn more about maths in brainly.com/question/25815188

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2 years ago