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melamori03 [73]
2 years ago
6

6 sin 2 ⁡ x + 4 cos 2 ⁡ x ≡ A + B cos 2 ⁡ x where A and B are integers. Work out the values of A and B .

Mathematics
1 answer:
almond37 [142]2 years ago
7 0

\textit{Pythagorean Identities} \\\\ sin^2(\theta)+cos^2(\theta)=1\implies sin^2(\theta)=1-cos^2(\theta) \\\\[-0.35em] ~\dotfill\\\\ 6sin^2(x)+4cos^2(x)\implies 6[~1-cos^2(x)~]+4cos^2(x) \\\\\\ 6-6cos^2(x)+4cos^2(x)\implies \stackrel{A}{6}~~ \stackrel{B}{-2}cos^2(x)

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Plz :<
maria [59]

Answer:

the answer must be A

Step-by-step explanation:

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professor190 [17]

Answer:

Opt. D.

Step-by-step explanation:

To solve this problem we need to focus our attention in the abs(x-1) function,

If x>1, then abs|x-1|= x-1, if x<1 then abs|x-1|= 1-x. And in the two intervals, the function opens upwards.

But our function has -3 multiplying abs|x-1|, This means that our function opens downward.

The vertex point can be found when x=1, since abs(x-1)=0. this gives f(1)=12

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krek1111 [17]

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Step-by-step explanation: f=final score

x= 77.7

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33 is 50% of what number ?
Vinvika [58]
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This is a sort of difficult question but i would highly appreciate assistance.
vivado [14]

Answer:

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Step-by-step explanation:

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