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melamori03 [73]
2 years ago
6

6 sin 2 ⁡ x + 4 cos 2 ⁡ x ≡ A + B cos 2 ⁡ x where A and B are integers. Work out the values of A and B .

Mathematics
1 answer:
almond37 [142]2 years ago
7 0

\textit{Pythagorean Identities} \\\\ sin^2(\theta)+cos^2(\theta)=1\implies sin^2(\theta)=1-cos^2(\theta) \\\\[-0.35em] ~\dotfill\\\\ 6sin^2(x)+4cos^2(x)\implies 6[~1-cos^2(x)~]+4cos^2(x) \\\\\\ 6-6cos^2(x)+4cos^2(x)\implies \stackrel{A}{6}~~ \stackrel{B}{-2}cos^2(x)

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Solve for all possible values of x. square root of the quantity x plus 6 end quantity plus 5 equals 17
Georgia [21]

Answer:

x=138

Step-by-step explanation:

So we have the equation:

\sqrt{x+6}+5=17

First, let's determine the domain restrictions. Recall that the radicand cannot be negative. In other words, it must be greater than or positive than 0. Thus:

x+6\geq 0

Subtract 6 from both sides:

x\geq -6

What this means is that our solutions must be greater than or equal to -6. If not, we ignore them.

So, let's subtract 5 from both sides from the original equation:

\sqrt{x+6}=12

Square both sides:

x+6=144

Subtract 6 from both sides:

x=138

138 is greater than -6, so 138 is a solution and is the only solution.

And we're done!

8 0
3 years ago
A soap factory randomly inspects 100 bars of soap to better identify problems that occur during the manufacturing process. The t
Rainbow [258]
150 I really hope it helped
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4 years ago
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AnnyKZ [126]

Answer:

x= 75

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Step-by-step explanation:

4 0
3 years ago
Which answer correct
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Answer:

A. 5000(.055)^t

Step-by-step explanation:

8 0
4 years ago
I have to rewrite an equation so that y is a function of x. I think I'm solving for Y, because on my examples it has "y=". How d
vivado [14]

You do whatever you need to do to one side of the equation in order to have
only ' y ' left on that side, AND every time you do something to that side of
the equation, do exactly the same thing to the other side.

Here are three examples, out of the 9 answers you want handed to you:

<em>#16:</em>                                  <u>3x + 5y = 7</u>

Subtract  3x  from each side:      5y = -3x + 7

Divide each side by  5 :                <em>y = -3/5 x + 7/5</em>

======================================

<em>#17: </em>                                    <u>13 = 12x - 2y</u>

Add  2y  to each side:    2y + 13 = 12x

Subtract 13  from each side:  2y = 12x - 13

Divide each side by  2 :         <em> y = 6x - 13/2</em>

======================================

<em>#22:</em>                                <u>1/4 y + 3 = -5x</u>

Subtract  3  from each side:   1/4 y = -5x + 3

Multiply each side by  4 :            <em>y = -20x + 12</em>


7 0
3 years ago
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