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4 years ago

12

PLEASE HELP! Which function is represented by the graph?

2 answers:

mr_godi [17]4 years ago

8 0

Answer:

Step-by-step explanation:

b

tigry1 [53]4 years ago

6 0

Answer:b

Step-by-step explanation:

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Jeni works from 8:00 - 3:15 three days in a row, only taking a half-hour unpaid lunch break each day. If she is paid $15 per hou

Umnica [9.8K]

Answer:

$101.25

Step-by-step explanation:

Given:

Jeni works from 8:00 - 3:15 three days

Taking a half-hour unpaid lunch break each day.

she is paid $15 per hour.

Question asked:

what will be her total earnings before tax ?

Solution:

Numbers of hours from 8:00 to 12 = 4 hours

Numbers of hours from 12:00 to 3:00 = 3 hours

Numbers of hours from 3:00 to 3:15 = 15 min = $\frac{15}{60}$ (converting min into hrs)

Total numbers of hours = 4 + 3 + $\frac{15}{60}$

= 7 + $\frac{15}{60}$ = 7 + 0.25

= 7.25 hours

Unpaid lunch break = half hours = 0.50 hours

Total number of hours for which she is paid = 7.25 - 0.50

= 6.75 hours

By applying unitary method :

In 1 hour she is paid = $15

In 6.75 hours she is paid = 15 $\times$ 6.75 = $101.25

Therefore, her total earnings before tax = $101.25

6 0

3 years ago

Find the distance between the points given.

Y_Kistochka [10]

So the answer is (C)

c.2/5

hope this HELP

3 0

3 years ago

What is cos(47)=x/3 solve for x

vlada-n [284]

X=141 ..............

4 0

3 years ago

kirill [66]

With 10 to the power to a negative number, it's easier.
Here's a trick: The negative number is the places to the right of the decimal. The last number is a 1, while the rest are 0s.

From this, we get: $10^{-4}=\boxed{0.0001}$

5 0

3 years ago

Read 2 more answers

Find an equation of the plane with the given characteristics. The plane passes through the points (4, 3, 1) and (4, 1, -7) and i

Minchanka [31]

Answer:

$3x - 4y + z = 1$

Step-by-step explanation:

Given

$Point\ 1 = (4,3,1)$

$Point\ 2 = (4,1,-7)$

Perpendicular to $8x + 7y + 4z = 18$

Required

Determine the plane equation

The general equation of a plane is:

$a(x-x_1) + b(y - y_1) + c(z-z_1) = 0$

For $n =$

$(x_1,y_1,z_1) = (4,3,1)$

$(x_2,y_2,z_2) = (4,1,-7)$

First, we need to determine parallel vector $V_1$

$V_1 =$

$V_1 =$

$V_1 =$

$V_1$ is parallel to the required plane

From the question, the required plane is perpendicular to $8x + 7y + 4z = 18$

Next, we determine vector $V_2$

$V_2 =$

This implies that the required plane is parallel to $V_2$

Hence: $V_1$ and $V_2$ are parallel.

So, we can calculate the cross product $V_1 * V_2$

$V_1 =$

$V_2 =$

$n = V_1 * V_2$

$V_1 * V_2 =\left[\begin{array}{ccc}i&j&k\\0&2&8\\8&7&4\end{array}\right]$

The product is always of the form + - +

So:

$V_1 * V_2 = i\left[\begin{array}{cc}2&8\\7&4\end{array}\right]$ $-j\left[\begin{array}{cc}0&8\\8&4\end{array}\right]$ $+k\left[\begin{array}{cc}0&2\\8&7\end{array}\right]$

Calculate the product

$V_1 * V_2 = i(2*4- 8*7) - j(0*4- 8*8) + k(0*7 - 2 * 8)$

$V_1 * V_2 = i(8- 56) - j(0- 64) + k(0 - 16)$

$V_1 * V_2 = i(-48) - j(- 64) + k(- 16)$

$V_1 * V_2 = -48i +64j - 16k$

So, the resulting vector, n is:

$n =$

Recall that:

$n =$

By comparison:

$a = -48$ $b = 64$ $c = -16$

Substitute these values in $a(x-x_1) + b(y - y_1) + c(z-z_1) = 0$

$-48(x-x_1) + 64(y - y_1) -16(z-z_1) =0$

Recall that: $(x_1,y_1,z_1) = (4,3,1)$

So, we have:

$-48(x-4) + 64(y - 3) -16(z-1) =0$

$-48x + 192 + 64y -192 - 16z +16 = 0$

Collect Like Terms

$-48x + 64y - 16z = 0 - 192 + 192 - 16$

$-48x + 64y - 16z = -16$

Divide through by -16

$3x - 4y + z = 1$

<em>Hence, the equation of the plane is</em> $3x - 4y + z = 1$ <em></em>

4 0

3 years ago