1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
alexandr1967 [171]
3 years ago
11

Jose's school is 4 km away. He walked 30 min at 5 km/hr when he realized he was running late and started running. How fast does

he need to to make it to school before the bell rings in 15 minutes.
Mathematics
1 answer:
FinnZ [79.3K]3 years ago
7 0

Answer:

Jose need to travel with a speed of 6 Km/hr to reach school in 15  minutes before the bell rings.

Step-by-step explanation:

Total distance from home to School = 4 km

Distance travelled by Jose in first 30 minutes is equal to

\frac{30}{60} * 5\\= 2.5

Distance to travel in next 15 minutes is equal to

4 -2.5 = 1.5 Km

Required speed

\frac{1.5}{\frac{15}{16} } \\= 1.5 * 4\\= 6

Jose need to travel with a speed of 6 Km/hr to reach school in 15  minutes before the bell rings.

You might be interested in
Calculator
Anna11 [10]

Answer:

The formula to calculate the total surface area of a cylinder is given as, the total surface area of cylinder = 2πr(h + r), while the curved surface area of cylinder formula is, curved/lateral surface area of cylinder = 2πrh, where 'r' is the radius of the base and 'h' is the height of the cylinder.

Step-by-step explanation:

hope it helps you

because I am not getting your answer

6 0
3 years ago
Read 2 more answers
PLS SOLVE THIS PAGE ASAP
d1i1m1o1n [39]
Y=mx+b
m is the slope rise/run and b is the y intercept plot the y intercept and from that point use the slope to find the next points. does that help any
3 0
3 years ago
Solve for x. Show your work.
puteri [66]
So, these are actually pretty simple once you learn the equality used to solve for "x" and when to implement this method. You can use this equality to solve for a segment "x" anytime that two secant lines cutting through a circle come from the same point outside the circle. 

Secant: by geometric definition is just a straight line that cuts a curve into multiple pieces.

I did one of them for you hopefully you can use my work for "a" to help you solve for "b".  For a. I got x=7.

6 0
4 years ago
Factor 6 out of <img src="https://tex.z-dn.net/?f=6x%5E2" id="TexFormula1" title="6x^2" alt="6x^2" align="absmiddle" class="late
boyakko [2]

Answer:

See below

Step-by-step explanation:

  • 6x² - 18 =
  • 6*x² - 6*3 =
  • 6(x² - 3)
6 0
2 years ago
Read 2 more answers
What is the measure of ∠BCD?<br><br><br><br> Enter your answer in the box.<br> °<br><br> PLSSS help
denpristay [2]
It seems to be a tilted square, so all angles are the same.
103 \times 3
so maybe just multiply by 3 and get 309 since B, C, and D are three angles.
103 \times 3 = 309
I might be wrong but, the answer should be 309.
8 0
3 years ago
Other questions:
  • Which equation represents the total interest, T, earned when the principal amount is $100, the annual simple
    9·2 answers
  • A scientist counts 35 bacteria present in a culture and finds that the number of bacteria triples each hour. The function y = 35
    10·2 answers
  • A polynomial is to be constructed that will touch the x axis at most 7 times. What is the minimum degree of the polynomial ?
    14·1 answer
  • Type of Book
    5·1 answer
  • Solve the following equation by first writing the equation in the form a x squared = c:
    8·2 answers
  • Start the mhanifa takeover. Everyone download the thumbs up, and change your profile pic.
    11·1 answer
  • If f(x) = 4x ^ 2 - 3 and g(x) = x + 1 , find (f - g)(x) O A. 4x ^ 2 - x - 2 B. x - 4x ^ 2 - 2 O C. 4x ^ 3 - 3 O D. 4x ^ 2 - x -
    8·1 answer
  • What is the surface area of this shape?​
    13·1 answer
  • Plz help and thank you
    11·2 answers
  • Help please I'm trying to get the answer for 3 3/5 divided by 1/6
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!