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Natali [406]
3 years ago
8

Which expression has twice the value of 2x2x2x2x2?

Mathematics
2 answers:
kolezko [41]3 years ago
6 0

Answer: 2⁶ = 64 is the twice the value of 2×2×2×2×2.

Step-by-step explanation:

Since we have given that

2×2×2×2×2 = 2⁵

We need to find the twice the value of the above expression :

So, it means

2×2⁵

As we know the law of exponents:

xᵃ × xᵇ = xᵃ⁺ᵇ

So, it becomes,

2× 2⁵ = 2⁵⁺¹ = 2⁶

So,  2⁶ = 64 is the twice the value of 2×2×2×2×2.

tester [92]3 years ago
3 0
16x(2). You would multiply 16 and 2. You have to find what x is though.
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Step-by-step explanation:

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3 years ago
The second term of a GP is 4, the fifth term is 81. Find the seventh term
navik [9.2K]

Answer:

The seventh term of a G.P is

t_{7}  = 33,097.211

Step-by-step explanation:

<u><em>step(i):</em></u><em>-</em>

<em>Given the second term of a G.P is '4'</em>

<em>The general term of nth term is </em>

<em></em>t_{n}  = ar^{n-1}<em></em>

<em></em>t_{4}  = ar^{4-1} =4  

ar^{3} =4 …(i)    

<em>Also Given the fifth term of a G.P is '81'</em>

t_{5}  = ar^{5-1} =81

ar^{4} =81  …(ii)      

<u><em>Step(ii)</em></u>:-

<em>Dividing the equation (ii) divided by (i)</em>

<em />\frac{ar^{4} }{ar^{3} } = \frac{81}{4}<em />

<em>cancellation ' a' and 'r' terms , we get</em>

<em />r = \frac{81}{4}=20.25<em />

<em>substituting 'r' Value in equation (i), we get</em>

<em></em>ar^{3} =4<em></em>

a(\frac{81}{4}) ^{3} =4  

a = \frac{4X4X4X4}{(81)^{3} }= \frac{256}{531,441}

a = 0.00048

<u><em>Step(iii):-</em></u>

<u><em>The seventh term of G.P </em></u>

<em>The general term of nth term is </em>

<em></em>t_{n}  = ar^{n-1}<em></em>

<em></em>t_{7}  = (0.00048)(20.25)^{7-1}<em></em>

<em></em>t_{7}  = (0.00048)(20.25)^{6}= 33,097.211<em></em>

<em></em>

<em></em>

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What is 81,007-26,318?
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54689

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