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Aleks04 [339]
4 years ago
5

What Is the y-intercept of y= 3 -4x?

Mathematics
1 answer:
liq [111]4 years ago
4 0

Answer:

3

Step-by-step explanation:

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6.81 is what percent of 45.5
frosja888 [35]

To get the solution, we are looking for, we need to point out what we know.

1. We assume, that the number 45.5 is 100% - because it's the output value of the task.

2. We assume, that x is the value we are looking for.

3. If 45.5 is 100%, so we can write it down as 45.5=100%.

4. We know, that x is 6.81% of the output value, so we can write it down as x=6.81%.

5. Now we have two simple equations:

1) 45.5=100%

2) x=6.81%

where left sides of both of them have the same units, and both right sides have the same units, so we can do something like that:

45.5/x=100%/6.81%

6. Now we just have to solve the simple equation, and we will get the solution we are looking for.


7. Solution for what is 6.81% of 45.5


45.5/x=100/6.81

(45.5/x)*x=(100/6.81)*x       - we multiply both sides of the equation by x

45.5=14.684287812041*x       - we divide both sides of the equation by (14.684287812041) to get x

45.5/14.684287812041=x

3.09855=x

x=3.09855

now we have:

6.81% of 45.5=3.09855

Hope this helps!

4 0
3 years ago
Read 2 more answers
What is the solution set to the inequality
creativ13 [48]

(4x - 3)(2x - 1) \geqslant 0 \\ \Leftrightarrow \begin{cases}4x - 3 \geqslant 0 \\ 2x - 1 \geqslant 0\end{cases}\: \vee \:\begin{cases}4x - 3 \leqslant 0 \\2x - 1 \leqslant 0 \end{cases} \\ \Leftrightarrow \begin{cases}x \geqslant  \frac{3}{4}  \\ x  \geqslant  \frac{1}{2} \end{cases}\: \vee \:\begin{cases}x\leqslant  \frac{3}{4}  \\x \leqslant  \frac{1}{2}  \end{cases} \\ \Leftrightarrow x \geqslant  \frac{3}{4} \: \vee \: x \leqslant  \frac{1}{2}  \\ \Rightarrow The\: third\: option

5 0
3 years ago
Read 2 more answers
Tim predicts he will get 98 points on the next exam. If Tim actually earned 62 points, what was Tim's percent error?
Nataly [62]

Answer:

If Tim actually earned 62 points . Therefore Tim's percent error is 58.1 % .

Step-by-step explanation:

3 0
3 years ago
There is a vendor at a carnival selling bags of cotton candy. Each bag of cotton candy has the same cost. She starts each day wi
umka21 [38]

Answer:

The cost of each cotton candy bag is $4.

Step-by-step explanation:

Consider the provided information.

Let, the vendor has x dollar at the starting of each day.

Let, the cost of each cotton candy bag is y.

Now when she sells a total of 12 bags, she has $128.

x+12y=128  .....(1)

After she sells a total of 20 bags, she has $160.

x+20y=160  ....(2)

Subtract equation 1 from equation 2.

(x+20y)-(x+12y)=160-128

8y=32

y=4

Hence, the cost of each cotton candy bag is $4.

6 0
3 years ago
Given: PRST is a square
xxTIMURxx [149]

Answer:

(1-\sqrt{2})a^2

Step-by-step explanation:

Consider irght triangle PRS. By the Pythagorean theorem,

PS^2=PR^2+RS^2\\ \\PS^2=a^2+a^2\\ \\PS^2=2a^2\\ \\PS=\sqrt{2}a

Thus,

MS=PS-PM=\sqrt{2}a-a=(\sqrt{2}-1)a

Consider isosceles triangle MSC. In this triangle

MS=MC=(\sqrt{2}-1)a.

The area of this triangle is

A_{MSC}=\dfrac{1}{2}MS\cdot MC=\dfrac{1}{2}\cdot (\sqrt{2}-1)a\cdot (\sqrt{2}-1)a=\dfrac{(\sqrt{2}-1)^2a^2}{2}=\dfrac{(3-2\sqrt{2})a^2}{2}

Consider right triangle PTS. The area of this triangle is

A_{PTS}=\dfrac{1}{2}PT\cdot TS=\dfrac{1}{2}a\cdot a=\dfrac{a^2}{2}

The area of the quadrilateral PMCT is the difference in area of triangles PTS and MSC:

A_{PMCT}=\dfrac{(3-2\sqrt{2})a^2}{2}-\dfrac{a^2}{2}=\dfrac{(2-2\sqrt{2})a^2}{2}=(1-\sqrt{2})a^2

5 0
3 years ago
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