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kogti [31]
3 years ago
8

Round the number 8.946 to the nearest tenth

Mathematics
1 answer:
Mumz [18]3 years ago
7 0

Answer:

8.9

Step-by-step explanation:

Because it is a 4, round down.

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What is the answer to 3/x=-3/3x+5
Aleonysh [2.5K]

Answer:

-\frac{5}{4} =x

Step-by-step explanation:

We first need to bring x up into the numerator. I will find common denominators by multiplying both sides by each denominator.

\frac{x(3x+5)}{1} *\frac{3}{x} =\frac{-3}{3x+5}*\frac{x(3x+5)}{1}

This will eliminate both denominators and leave me with

(3x+5)3=-3(x)\\9x+15=-3x after I simplify the parenthesis.

Now I will solve the equation for x by subtracting 9x from both sides.

9x-9x+15=-3x-9x\\15=-12x

Then divide by the coefficient of x.

\frac{15}{-12}=\frac{-12x}{-12}

-\frac{5}{4} =x


7 0
3 years ago
"A rectangle has a height of 5 cm and its base is increasing at a rate" of 3/2 cm/min. When its area is 60 cm2, at what rate is
sukhopar [10]

Answer:

The diagonal is increasing at the rate of 119/104cm/min of the given rectangle.

Step-by-step explanation:

Dimensions of the rectangle

Height = 5cm

Rate of base = 3/2 cm/min

Area = 60cm^2

We know the area of a rectangle of given by = base* Height

b*h = 60

b*5 = 60

b = 12cm

Applying Pythagoras theorem while drawing a diagonal to the rectangle

  b^2 +h^2 =  D^2\\

 5^2 +12^2 = 13^2

so our diagonal will be 13cm  

Upon differentiating the area of the rectangle  we get

b*h = A=60cm^2

using  the chain rule of differentiation

h*db/dt + b*dh/dt  = 0

b*dh/dt = -h*db/dt

12*dh/dt = -5*3/2

dh/dt = -5/8 cm//min

so the height of the rectangle is decreasing at the rate of -5/8cm/min

now we have all the measurements we need

b = 12 , db/dt = 3/2cm/min

h = 5 , dh/dt = -5/8 cm/min

b^2 +h^2  = D^2

Upon differentiating we get

2b*db/dt + 2h*dh/dt = 2D*dD/dt

b*db/dt + h*dh/dt = D*dD/dt

12*3/2 + 5*(-5/8) = 13*dD/dt

18 -25/8 = 13*dD/dt

\frac{144-25}{8} = 13*dD/dt

dD/dt = \frac{119}{104} cm/min

Therefore the diagonal is increasing at the rate of 119/104cm/min of the given rectangle.

6 0
3 years ago
Plz Help Brainliest To First Answer<br><br> In rhombus ABCD , m∠BCE=33∘ .<br><br> What is m∠ABE ?
Tamiku [17]

Answer:

57 deg

Step-by-step explanation:

Rhombus ABCD has diagonals AC and BD which intersect at point E.

The diagonals of a rhombus divide the rhombus into 4 congruent triangles.

If you find the measures of the angles of one of the triangles, then you know the measures of the angles of all 4 triangles.

Also, the diagonals of a rhombus are perpendicular.

Look at triangle BCE.

m<BCE = 33

m<BEC = 90

m<BCE + m<BEC + m<CBE = 180

33 + 90 + m<CBE = 180

m<CBE = 57

<ABE in triangle ABE corresponds to <CBE in triangle BCE.

m<ABE = m<CBE = 57

Answer: 57 deg

4 0
3 years ago
Suppose the heights of women at a college are approximately Normally distributed with a mean of 65 inches and a population stand
Zigmanuir [339]

Answer:

Step-by-step explanation:

Hello!

The variable of interest, X: height of women at a college, has an approximately normal distribution with mean μ= 65 inches and standard deviation σ= 1.5 inches.

You need to look for the value of height that marks the bottom 20% of the distribution, i.e. the height at the 20th percentile of the normal curve, symbolically:

P(X≤x₀)= 0.20

To know what value of height belongs to the 20% of the distribution, you have to work using the standard normal distribution and then reverse the standardization with the population mean and standard deviation to reach the value of X. So the first step is to look for the Z-value that accumulates 20% of the distribution:

P(Z≤z₀)=0.20

z₀= -0.842

z₀= (x₀-μ)/σ

z₀*σ= (x₀-μ)

x₀= (z₀*σ)+μ

x₀= (-0.842*1.5)+65

x₀= 63.737 inches

I hope it helps!

6 0
3 years ago
Read 2 more answers
Find the common difference of the arithmetic sequence -4, 1, 6,...
Serggg [28]
4 I think is the right answer but I’m not sure so sorry if u get this wrong
6 0
1 year ago
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