Answer:
16,200 im not sure if its right just multiply everything then add to multiplication x3
THE AREA IS 20 UNITS BECAUSE IF YOU DIVIDE IT INTO 2 SQUARES, THE FIRST ONE IS 4*3=12. THE SECOND ONE IS 2*4=8.
12+8=20.
HOPE THIS HELPED☺☺
(-7,-12) s it both down and to the right of the origin
- Length (l) = 45 m
- Breadth (b) = 30 m
- We know, perimeter of a rectangle = 2(length + breadth)
- Therefore, perimeter of the rectangle
- = 2(I + b)
- = 2(45 + 30) m
- = 2 × 75 m
- = 150 m
- So, the distance travelled by Rubina
- = 4 × 150 m
- = 600 m
<u>Answer:</u>
<em><u>The </u></em><em><u>distance </u></em><em><u>travelled</u></em><em><u> </u></em><em><u>by </u></em><em><u>Rubina </u></em><em><u>is </u></em><em><u>6</u></em><em><u>0</u></em><em><u>0</u></em><em><u> </u></em><em><u>m.</u></em>
Hope you could get an idea from here.
Doubt clarification - use comment section.
1) function f(x)
x - 5
f(x) = ----------------
3x^2 - 17x - 28
2) factor the denominator:
3x^2 - 17x - 28 = (3x + 4)(x - 7)
x - 5
=> f(x) = -----------------------
(3x + 4) (x - 7)
3) Find the limits when x → - 4/3 and when x → 7
Lim of f(x) when x → - 4/3 = +/- ∞
=> vertical assymptote x = - 4/3
Lim of f(x) when x → 7 = +/- ∞
=> vertical assymptote x = 7
Answer: there are assympotes at x = 7 and x = - 4/3