Given:
Length of rectangle = (x+10) cm
Width of the rectangle = x cm
Perimeter = 32 cm
To find:
The length of the rectangle.
Solution:
We know that,
![Perimeter=2(l+w)](https://tex.z-dn.net/?f=Perimeter%3D2%28l%2Bw%29)
Where, l is length and w is width.
Substituting the values, we get
![32=2((x+10)+x)](https://tex.z-dn.net/?f=32%3D2%28%28x%2B10%29%2Bx%29)
![32=2(2x+10)](https://tex.z-dn.net/?f=32%3D2%282x%2B10%29)
![32=4x+20](https://tex.z-dn.net/?f=32%3D4x%2B20)
Subtract 20 from both sides.
![32-20=4x](https://tex.z-dn.net/?f=32-20%3D4x)
![12=4x](https://tex.z-dn.net/?f=12%3D4x)
Divide both sides by
![3=x](https://tex.z-dn.net/?f=3%3Dx)
So, the length is
![3+10=13](https://tex.z-dn.net/?f=3%2B10%3D13)
Therefore, the length of the rectangle is 13 cm.
The first option .
.................................
Answer:
False
Step-by-step explanation:
You can only get a two by rolling 2 ones
you can get a three by rolling a 1 and 2
They both only have 1 option to roll on too. So the answer is false, with 2 die the probibility will be the same.
Answer:
89.29%
Step-by-step explanation:
Given that Scott answered exactly two questions wrong. He answered the last question wrong, the 26 questions before it correctly, and the question before that wrong. Since Amy and Scott were both incorrect on the same question exactly once, Scott would have done wrong only in I or II or III question. If I question was wrong by both, total questions = 28, if II wrong total questions =29 and for iii total questions =30
Greatest possible percent would occur if total questions are less
i.e. when total =28
Greatest percent = ![\frac{28-3}{28} =89.29%](https://tex.z-dn.net/?f=%5Cfrac%7B28-3%7D%7B28%7D%20%3D89.29%25)
Answer:
3.5
Step-by-step explanation: