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galben [10]
4 years ago
13

Rosa and her brother worked landscaping jobs last summer. Rosa earned $8 more than twice the amount earned by her brother. If th

eir earnings totalled $71, how much did Rosa earn? NEED AN ANSWER
Mathematics
1 answer:
nadezda [96]4 years ago
4 0
Rosa earned $50

Explanation:

Two people Rosa & her brother
Her brother earns X
While Rosa earns 2X + 8
Now we gotta solve for X

They made $71. $71 minus X should give you Rosa’s pay

71 - X = 8 + 2X (subtract 8 from 71)
63 - X = 2X (add X to 2X)
63 = 3X (divide by 3)
21 = X

Plug in $21 for Rosa:
8 + 2(21)
8 + 42 = $50




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Gwar [14]
3/4=21/28
2/7=8/28
so
21/28-8/28=13/28
answer =13/28
6 0
3 years ago
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user100 [1]

Answer:

1. A 2.C 3.D 4.B 5. A PORK-U-PINE

Step-by-step explanation:

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3 years ago
Find the volume of the figure.
Andre45 [30]

Answer:

12

Step-by-step explanation:

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8 0
3 years ago
The population of a city has been increasing by 2% annually. In 2000, the population was 315,000. Predict the population of the
Minchanka [31]

Answer:

The population of the city in 2020 is 3,839,832

Step-by-step explanation:

Given:

Population at 2000 =  315,000

Rate at which the population increases = 2%

To Find:

The Population in the city after 2020 = ?

Solution:

The population in the city after 2020 can be found by using Exponential growth function.

Exponential growth occurs when a quantity increases by the same factor

Exponential growth function is y = a(1 + r)^t

Where

y is the final amount

a is the initial amount

r is the rate of  increase

t is the time period.

Now substituting the values ,

In 2020 i.e., after 10 years

y = 315000(1 + 2 \%)^{10}

y = 315000(1 + \frac{2}{100})^{10}

y = 315000(1 + 0.02)^{10}

y = 315000(1.02)^{10}

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4 0
3 years ago
PLEASE HELP! 25 PTS!!
zubka84 [21]

Answer:

Solution given:

f(x)=\frac{x-16}{x^2+6x-40}

g(x)=\frac{1}{x+10}

now

f(x)+g(x)=\frac{x-16}{x^2+6x-40}+\frac{1}{x+10}....(1)

now

factoring x²+6x-40

we get

x²+10x-4x-40

x(x+10)-4(x+10)

(x+10)(x-4)

now substituting in equation 1 ,we get

f(x)+g(x)=\frac{x-16}{(x+10)(x-4)}+\frac{1}{x+10}

taking l.c.m

=\frac{(x-16)+(x-4)}{(x-10)(x-4)}

=now

opening bracket

\frac{x-16+x-4}{x²-10x-4x+40}

=\frac{2x-20}{x²+6x-40}

So

answer is :

B. \bold b\frac{2x-20}{x^2+6x-40}

6 0
3 years ago
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