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aleksley [76]
3 years ago
5

Can i please get help with this question?

Mathematics
1 answer:
Feliz [49]3 years ago
4 0

The first letter because 1•5 = 5. 2•5 equals ten etc

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What is a number t divided by 3 in algebraic expression
bogdanovich [222]

t/3 is your expression.

feel free to add me as a friend as I am very good at math.

7 0
3 years ago
angel's dad bought a television for her completing all of her digital learning day lesson. he want to warp the gift. the box mea
atroni [7]

Answer: 13 sheets of paper

Step-by-step explanation:

We are given the dimensions of the box and the wrap paper:

Box:

(56 in)(8 in)(36 in)

Warp paper:

(26 in)(17 in)

Now we need to find the surface area of the box and the area of the wrap paper:

Box:

surface_{1}=(56 in)(8 in)(2)=896 in^{2}

surface_{2}=(8 in)(36 in)(2)=576 in^{2}

surface_{3}=(56 in)(36 in)(2)=4032 in^{2}

surface-area=896 in^{2}+576 in^{2}+4032 in^{2}=5504 in^{2}

Warp paper:

area=(26 in)(17 in)=442 in^{2}

Dividing the area of the box by the area of the paper:

\frac{surface-area}{area}=\frac{5504 in^{2}}{442 in^{2}}=12.45 \approx 13

This means Angel's dad needs to purchase 13 sheets of wrapping paper.

4 0
3 years ago
A parabola has a vertex at (4, 0) and passes through the point (6, 1). Which of the following is the equation of this parabola i
Doss [256]
Easy

y=a(x-h)^2+k
vertex is (h,k)
we know that vertex is (4,0)
input that point for (h,k)
y=a(x-4)^2+0
y=a(x-4)^2
passes thorugh the point (6,1)
input that point to find a
1=a(6-4)^2
1=a(2)^2
1=a(4)
divide both sides by 4
1/4=a

thefor the equation is
y=(1/4)(x-4)^2
or
y=(1/4)x^2-2x+4
7 0
3 years ago
If you roll two fair dice repeatedly, what is the probability that you will get a sum of 4 before you get a sum of 5 ? (a) (b) (
AlexFokin [52]

Answer:

The probability that you will get a sum of 4 before you get a sum of 5 is \frac{1}{12}

Step-by-step explanation:

Given : If you roll two fair dice repeatedly.

To find : What is the probability that you will get a sum of 4 before you get a sum of 5 ?

Solution :

When two dice are rolled the outcomes are

(1,1) (1,2) (1,3) (1,4) (1,5) (1,6)

(2,1) (2,2) (2,3) (2,4) (2,5) (2,6)

(3,1) (3,2) (3,3) (3,4) (3,5) (3,6)

(4,1) (4,2) (4,3) (4,4) (4,5) (4,6)

(5,1) (5,2) (5,3) (5,4) (5,5) (5,6)

(6,1) (6,2) (6,3) (6,4) (6,5) (6,6)

Total number of outcomes = 36

Favorable outcome get a sum of 4 before you get a sum of 5 is (1,3) ,(2,2) and (3,1) = 3

The probability that you will get a sum of 4 before you get a sum of 5 is

P=\frac{3}{36}

P=\frac{1}{12}

Therefore, The probability that you will get a sum of 4 before you get a sum of 5 is \frac{1}{12}

5 0
3 years ago
The heights of American men aged 18 to 24 are approximately normally distributed with mean 68 inches and standard deviation 2.5
MissTica

Answer:

78.81

Step-by-step explanation:

6 0
3 years ago
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