Help me please I forgot my notes at school

Mathematics

2 answers:

sukhopar [10]3 years ago

6 0

1/2 x 6 = 3
3 x 8 = 24
24/6 = 4
4 - 1 = 3

3 is your answer

hope this helps

natulia [17]3 years ago

4 0

Because of BIDMAS, we know to do the brackets first
so it would be 3 * 8 ÷ 6 - 1
Division and multiplication next, so 4 -1
Lastly, subtraction
3

I am not 100% sure this answer is right but this is system I was taught
Hope it helped

You might be interested in

In one jar, I have two balls labelled 1 and 2 respectively. In a second jar, I have three balls labelled 0, 1 and 2 respectively

PolarNik [594]

Step-by-step explanation:

this is a kind of trick question, actually.

with whatever we draw, we produce X values as power of 3.

to be precise, we can have only

3⁰ = 1

3¹ = 3

3² = 9

3⁴ = 81

due to the possible combinations of drawn numbers (e.g. 3 cannot be created by a multiplication of 0s, 1s and 2s).

so, mostly, these results cannot be exact factors of 1024.

1024 cannot be divided by 3, nor by 9 nor by 81.

but 1024 is a multiple of 1 (as is every number).

so, we are looking at the probability to get 0 as multiplication result of the numbers on the 2 drawn balls.

the only possibilities are

1 and 0

2 and 0

out of in total 6 (2×3) different outcomes

1 and 0

1 and 1

1 and 2

2 and 0

2 and 1

2 and 2

the probability of this "0" event is again

number of desired outcomes / number of possible outcomes = 2/6 = 1/3

6 0

3 years ago

How do u work this out and what's the answer

I am Lyosha [343]

1) you would need to turn both fractions so they have a common denominator, that would be 2 2/4 and 3/4
2) then subtract : 2 2/4 - 3/4, and you would subtract numerators and the whole number, but you keep the denominator the same. However, you cannot subtract 2 and 3 in this case, so you need to change 2 2/4 to 1 5/4 (they are still equivalent)
3) 1 5/4 - 3/4 = 1 2/4, which simplified version is 1 1/2
Therefore, the answer is 1 and 1/2

6 0

3 years ago

Can you please explain and answer this question to me, (don't mind the blue dots, they are the answers of what I think, please l

Fofino [41]

I started with c, but you could’ve started with any box.

So I took the numbers in the c box (the black box in my picture) and divided to see which were multiples of two. They all were.

Then I went to a. All of a’s numbers were divisible by 7.

Then b. Two of them are divisible by 2, so that’s not the answer. None of them were divisible by 7, so there’s your answer!

Then d. Two are divisible by 7, so your rules is divisible by 2.

I hope this helps!