If we assume the given segments are those from the vertices to the point of intersection of the diagonals, it seems one diagonal (SW) is 20 yards long and the other (TR) is 44 yards long. The area (A) of the kite is half the product of the diagonals:
... A = (1/2)·SW·TR = (1/2)·(20 yd)·(44 yd)
... A = 440 yd²
Answer:
.25
Step-by-step explanation:
Angle A = 30 and its complement would be 60. This is because both angles must equal 90 degrees, and 30 + 60 = 90. Also in the directions it states Angle A must be half of its complement. 30 is half of 60. Sorry I don’t have any work, I just did it in my head!
Any questions? Hope this helps!
Answer:
13/28 (13 over 28)
Step-by-step explanation:
26/28 - 13/28 = 13/28 and since 13 is a prime number it can't be simplified
