Answer:
Option B is right
Step-by-step explanation:

(One tailed test at 5% significance level)
n =16 and x bar =1.97
s =0.1
Std error of mean = 
Mean diff = 
t statistic =Mean diff/se =-1.2
df =16-1=15
p value =0.124375
(B) do not reject the null because the test statistic (-1.2) is > the critical value (-1.7531).
2.4x10 to the power of -10
Answer:

Step-by-step explanation:
