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Tpy6a [65]
4 years ago
13

Help me please? ASAP. 10 points??

Mathematics
1 answer:
alex41 [277]4 years ago
8 0

Answer:

D) 16x^2 + 4x


Step-by-step explanation:

So a since there is two lengths and two height, you are gonna have to add them all up.

<u>5x^2 + 2x</u> + <u>5x^2 + 2x</u> + <u>3x^2</u> + <u>3x^2</u>

<u>(</u>See why I put the length value and width value twice? Because there is two of each.)

Now start adding up common factors. Let's start with any x^2

10x^2+2x + 2x + 6x^2

I added up the 5x^2 together to get 10x^2 and I added the 3x^2 together to get 6x^2, now you are gonna add those two up

16x^2 + 2x + 2x

(Just from looking at this, you can easily cross out answers A and B)

Now add the x together

16x + 4x

So the the answer is D

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Joe and Beth both wash cars for extra cash. Joe charges a base fee of $15 and $8 per car after that. Beth charges a base fee of
Ksenya-84 [330]

Answer:

C- 15 cars.

Step-by-step explanation:

To do this, you will need to set up an equation as follows:

8x+15=6x+45

Then you will subtract 6x from each side. Then you will have this:

2x+15=45

Then you will subtract 15 from each side, and then you will have:

2x=30

Then you will divide each side by 2 and you will get 15. Hope this helped!

8 0
4 years ago
Slope-Intercept Form of 3x – 4y – 16 = 0
mojhsa [17]

Answer:

Y= 3/4x - 4

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Dwayne Wade made 439 field goals out of 937 attempts. What was Dwayne Wade's ratio of successful field goals to attempt?
Serhud [2]
Let's set this ratio up as a fraction: (successful field goals)/(field goal attempts)
There were 439 successful field goals and 937 attempts: 439/937
The fraction cannot be reduced, so the ratio is 439/937.
8 0
3 years ago
Read 2 more answers
10.
Kay [80]

Answer:

\frac{(82)(2.4)^2}{104.139} \leq \sigma^2 \leq \frac{(82)(2.4)^2}{62.132}

4.535 \leq \sigma^2 \leq 7.602

Now we just take square root on both sides of the interval and we got:

2.2 \leq \sigma \leq 2.8

And the best option would be:

A.  2.2 < σ < 2.8

Step-by-step explanation:

Information provided

\bar X=32.1 represent the sample mean

\mu population mean  

s=2.4 represent the sample standard deviation

n=83 represent the sample size  

Confidence interval

The confidence interval for the population variance is given by the following formula:

\frac{(n-1)s^2}{\chi^2_{\alpha/2}} \leq \sigma^2 \leq \frac{(n-1)s^2}{\chi^2_{1-\alpha/2}}

The degrees of freedom are given by:

df=n-1=83-1=82

The Confidence is given by 0.90 or 90%, the value of \alpha=0.1 and \alpha/2 =0.05, the critical values for this case are:

\chi^2_{\alpha/2}=62.132

\chi^2_{1- \alpha/2}=104.139

And replacing into the formula for the interval we got:

\frac{(82)(2.4)^2}{104.139} \leq \sigma^2 \leq \frac{(82)(2.4)^2}{62.132}

4.535 \leq \sigma^2 \leq 7.602

Now we just take square root on both sides of the interval and we got:

2.2 \leq \sigma \leq 2.8

And the best option would be:

A.  2.2 < σ < 2.8

3 0
3 years ago
What is the value of y?
mrs_skeptik [129]
Ok so you would start by getting rid of the fraction. You should know the steps for that by now but here this is what it would look like
3y/4+10=2y/4 Simplify
3y/4+10=1y/2
10=-1y 
I really simplified the last part but this is what it looks like:  \frac{2y}{4}- \frac{3y}{4} = -1y
10=-1y
y=-10
8 0
3 years ago
Read 2 more answers
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