The length of a rectangle is 2 cm more than four times the width. If the perimeter of the rectangle is 84 cm, what are its dimen
sions
1 answer:
Answer:
Length 34 cm
Width 8 cm
Step-by-step explanation:
Let
x-----> the length of the rectangle
y----> the width of the rectangle
we know that
The perimeter of rectangle is equal to
P=2(x+y)
P=84 cm
so
84=2(x+y)
42=x+y ----> equation A
x=4y+2 -----> equation B
substitute equation B in equation A and solve for y
42=(4y+2)+y
5y=42-2
y=40/5=8 cm
Find the value of x
x=4y+2 ----> x=4(8)+2=34 cm
The dimensions are
Length 34 cm
Width 8 cm
You might be interested in
Yeah i don’t know the answer but don’t press those links they are hackers
9 cuz 4 times 1/2 is 2 and 2+7=9
If there is no more informations, then:
<h2> A =
¹/₃(6 + x)</h2>
Y = mx + b
where m = slope and b = y-intercept
y = (9/4)x - 4
or 4y = 9x - 16
It’s impossible what are you doing Distributed property or solving for x?