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Alla [95]
3 years ago
6

What molecule is produced in the citric acid cycle as a by-product of glucose oxidation and is considered a waste product?

Physics
1 answer:
cluponka [151]3 years ago
6 0

Are there answer choices?

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A flat coil of wire consisting of 15 turns, each with an area of 40 cm 2, is positioned perpendicularly to a uniform magnetic fi
zheka24 [161]

Answer:

0.54 A

Explanation:

Parameters given:

Number of turns, N = 15

Area of coil, A = 40 cm² = 0.004 m²

Change in magnetic field, ΔB = 5.1 - 1.5 = 3.6 T

Time interval, Δt = 2 secs

Resistance of the coil, R = 0.2 ohms

To get the magnitude of the current, we have to first find the magnitude of the EMF induced in the coil:

|V| = |(-N * ΔB * A) /Δt)

|V| = | (-15 * 3.6 * 0.004) / 2 |

|V| = 0.108 V

According to Ohm's law:

|V| = |I| * R

|I| = |V| / R

|I| = 0.108 / 0.2

|I| = 0.54 A

The magnitude of the current in the coil of wire is 0.54 A

6 0
3 years ago
Which is the work required to move a charge?
bulgar [2K]

Answer:

O electric potential

Explanation:

3 0
3 years ago
Read 2 more answers
One of the great upcoming sports in the Olympics is the sport of curling. Write a brief essay on the uses of momentum collisions
Svetllana [295]

The Olympic sport of curling is one that is practically designed to show Physics in motion. Curling is a sport in which two teams alternate sliding smoothed stone pucks down an ice rink court with the intent to seat their stone closest to the center of the target (called the house). Each team has eight stones, meaning that the team that goes second has the (could be) massive advantage of sending the last stone.  

The mass of the stone is important in that the more massive a stone (m) and the speed at which it travels (v) dictates it's momentum (momentum=mxv). As the curling stone slides down the ice (which is relatively frictionless unless acted upon by other players or objects) and having inertia, continues in it's straight course (again, unless acted upon by outside forces). If the stone hits another stone, it transfers some of its momentum in an elastic collision to that stone and the original stone is deflected in a calculable manner.    

Collisions are used in the game to either clear opponent's stones from the house or out of their defensive positions, or to make adjustments to one's stones present in the house, all based on the momentum of the moving stone, and its transference.

6 0
3 years ago
A block is projected up a frictionless inclined plane with initial speed v0 = 7.14 m/s. The angle of incline is θ = 36.5°. (a) H
Wewaii [24]

Answer:

(a)x=4.37m\\\\(b)t=1.225s\\\\(c) v_{f}=7.14m/s

Explanation:

Given data

v_{o}=7.14m/s\\\alpha =36.5^o

For Part (a)

Starting with the -ve acceleration of the body (opposite to the gravitational force)

a=-gSin\alpha \\a=-(9.8m/s^2)Sin(36.5)\\a=-5.83m/s^2

Using equation of motion

v_{f}^2=v_{o}^2+2ax\\(0m/s)^2=(7.14m/s)^2+2(-5.83m/s^2)x\\-(7.14m/s)^2=2(-5.83m/s^2)x\\x=\frac{-(7.14m/s)^2}{2(-5.83m/s^2}\\ x=4.37m

For Part (b)

Using the result in Part (a) we can substitute in other equation of motion to get time t:

x=\frac{1}{2}vt\\ 4.37m=\frac{1}{2}(7.14m/s)t\\ (7.14m/s)t=2*(4.37)\\t=8.744/7.14\\t=1.225s

For Part (c)

At state 2 where vo=0m/s and the acceleration is positive (same direction as the gravitational force)

a=gSin\alpha \\a=(9.8m/s^2)Sin(36.5)\\a=5.83m/s^2\\\\\\v_{f}^2=v_{o}^2+2ax\\v_{f}^2=(0m/s)^2+2(5.83m/s^2)(4.37m)\\v_{f}^2=50.95\\v_{f}=\sqrt{50.95}\\ v_{f}=7.14m/s

4 0
3 years ago
The human eye is most sensitive to green light of wavelength 505 nm . Experiments have found that when people are kept in a dark
liq [111]

1. 5.94\cdot 10^{14} Hz

The frequency of a photon is given by:

f=\frac{c}{\lambda}

where

c is the speed of light

\lambda is the wavelength

The wavelength of the photon in this problem is

\lambda=505 nm=5.05\cdot 10^{-7}m

So, the frequency of the photon is

f=\frac{3\cdot 10^8 m/s}{5.05\cdot 10^{-7} m}=5.94\cdot 10^{14} Hz

2. 3.94\cdot 10^{-19}J, 2.46 eV

The energy of a photon is given by

E=hf

where

h is the Planck constant

f is the frequency of the photon

The frequency of the photon in this problem is

f=5.94\cdot 10^{14} Hz

so its energy in Joules is

E=(6.63\cdot 10^{-34}Js)(5.94\cdot 10^{14}Hz)=3.94\cdot 10^{-19}J

And since

1 eV = 1.6\cdot 10^{-19}J

The energy in eV is

E=\frac{3.94\cdot 10^{-19} J}{1.6\cdot 10^{-19}J/eV}=2.46 eV

7 0
3 years ago
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