P = mv
p = (1600kg)(20m/s)
p = 32000 N
(3.2x10^4 N)
Answer:
Right shoe
Explanation:
Let the mass and velocity of incoming puck be m and v respectively.
Momentum of the colliding puck will be mv
In case of first case , the momentum of puck becomes zero so change in momentum after collision with left shoe
= mv - 0 = mv
If time duration of collision be t
rate of change of momentum
= mv / t
This is the force exerted by puck on the left shoe .
Now let us consider collision with right shoe
momentum after collision with right shoe
- mv
change in momentum
= mv - ( - mv ) = 2mv
If time duration of collision be t
rate of change of momentum
= 2mv / t
This is the force exerted by puck on the right shoe .
Since the force on the right shoe is more , this shoe will have greater speed
after collision.
<h2>
Answer:5
,133.6
,51.18
</h2>
Explanation:
Let , be the horizontal and vertical components of velocity.
Question a:
Horizontal component of velocity is the ratio of range and time of flight.
So,horizontal component of velocity is
So,
Question b:
Time of flight=
So,
Maximum height is given by
So,maximum height is
Question c:
The vertical velocity is already calculated in Question b.
You go to the image, click edit, then you click this square with arrows around it, then you look up at the left corner of your screen and you click the square with the arrow and adjust the image to your liking.
This is A, true, because no matter what you do, it will have a reaction that happens.