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3 years ago

Five times the larger of two consecutive odd integers is equal to one more than eight times the smaller

Mathematics

1 answer:

Dennis_Churaev [7]3 years ago

4 0

Answer:

SMALLER INTEGER = 3

LARGER INTEGER = 5

Step-by-step explanation:

Given the following :

Five times the larger of two consecutive odd integers is equal to one more than eight times the smaller

Let the larger = L, smaller = L - 2

5 × L = 8(L - 2) + 1

5L= 8L - 16 + 1

5L = 8L - 15

5L - 8L = - 15

-3L = - 15

Divide both sides by 3

L = 5

The smaller integer will be (L - 2)

(L - 2) = (5 - 2) = 3

HENCE, SMALLER INTEGER = 3

LARGER INTEGER = 5

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Carter divided the polynomial 6x2 + 4x + 3 by the monomial 2x using long division, and got an answer of 3x + 2 + . His work is s

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Answer:

C. Both Carter and Demi are correct and would get the same answer.

Step-by-step explanation:

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Now, according to the given question:

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Now, Carter divide P(x) by Q (x) with LONG DIVISION METHOD.

If we divide P(x) by Q(x) by Long division, we get:

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Hence, Both Carter and Demi are correct and would get the same answer.

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Five times the larger of two consecutive odd integers is equal to one more than eight times the smaller​

Five times the larger of two consecutive odd integers is equal to one more than eight times the smaller