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Ilya [14]
3 years ago
10

Five times the larger of two consecutive odd integers is equal to one more than eight times the smaller​

Mathematics
1 answer:
Dennis_Churaev [7]3 years ago
4 0

Answer:

SMALLER INTEGER = 3

LARGER INTEGER = 5

Step-by-step explanation:

Given the following :

Five times the larger of two consecutive odd integers is equal to one more than eight times the smaller​

Let the larger = L, smaller = L - 2

5 × L = 8(L - 2) + 1

5L= 8L - 16 + 1

5L = 8L - 15

5L - 8L = - 15

-3L = - 15

Divide both sides by 3

L = 5

The smaller integer will be (L - 2)

(L - 2) = (5 - 2) = 3

HENCE, SMALLER INTEGER = 3

LARGER INTEGER = 5

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Answer:

The answer is C.

Step-by-step explanation:

Multiply 4 by 76, 77, and 78.

4 * 76 = 304

4 * 77 = 308

4 * 78 = 312

304 = 304, so C is the correct answer.

Hope this helps!

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The profit y (in dollars) for a company for selling x games is represented by y=32x. Graph the equation. ANSWER BEFORE 11 FOr BO
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Answer:

I guess that we have the linear equation:

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Then the first step may be doing a table.

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2 years ago
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Hunter-Best [27]

El volumen que queda entre la esfera y el cubo es:  30.49cm^3

<h3>¿Como calcular el volume sobrante?</h3>

El volumen sobrante será simplemente la diferencia entre el volumen del cubo y el volumen de la esfera.

Para el cubo que tiene una arista de 4cm, el volumen es:

V = (4cm)^3 = 64 cm^3

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R = 4cm/2 = 2cm

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El volumen que queda entre la esfera y el cubo es:

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Sí quieres aprender más sobre volumenes:

brainly.com/question/1972490

#SPJ1

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