Five times the larger of two consecutive odd integers is equal to one more than eight times the smaller
1 answer:
Answer:
SMALLER INTEGER = 3
LARGER INTEGER = 5
Step-by-step explanation:
Given the following :
Five times the larger of two consecutive odd integers is equal to one more than eight times the smaller
Let the larger = L, smaller = L - 2
5 × L = 8(L - 2) + 1
5L= 8L - 16 + 1
5L = 8L - 15
5L - 8L = - 15
-3L = - 15
Divide both sides by 3
L = 5
The smaller integer will be (L - 2)
(L - 2) = (5 - 2) = 3
HENCE, SMALLER INTEGER = 3
LARGER INTEGER = 5
You might be interested in
456 divided by 12= 38
Therefore his car travelled 38 miles per gallon of gas used.
Answer:
Step-by-step explanation:
(3, 0) (4, 1)
(1 - 0)/(4 - 3)= 1/1= 1
y - 0 = x - 3
y = x - 3
Answer:
hope this helps you with your question
Answer:
domain d is the answer
Step-by-step explanation:
your welcome
Answer:
7 i think because 10-3 =7
also 3+7 =10
Step-by-step explanation:
