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Umnica [9.8K]
3 years ago
9

I’ll type it out if you can’t see it well

Mathematics
2 answers:
3241004551 [841]3 years ago
6 0

Answer:

D) Multiplication should be performed before addition

ra1l [238]3 years ago
3 0
D,because multiplication should come before addition(pemdas)
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STALIN [3.7K]

Answer:

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3 years ago
Please help on b (left of c) and c !!!
vesna_86 [32]
Alrighty


remember
(ab)^c=(a^c)(b^c)
and
x^\frac{m}{n}=\sqrt[n]{x^m}
and
(x^m)^n=x^{mn} and [tex]x^0=1 for all real numbers x
and
x^{-m}=\frac{1}{x^m}


b.
(x^5y^4)^\frac{1}{2}=((x^5)^\frac{1}{2})((y^4)^\frac{1}{2})=
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c.
x^0=1
so
that (x^-3y)^0=1
because exponents first in pemdas
so we are left with
x^2y^-1
x^2y^{-1}=(x^2)(y^{-1})=(x^2)(\frac{1}{y^1})=\frac{x^2}{y}
3 0
3 years ago
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